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P value is 0.036 Two types of valves are being tested to determine if there is a difference in pressure tolerances. Fifteen out of a

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P value is 0.036

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Two types of valves are being tested to determine if there is a difference in pressure tolerances. Fifteen out of a random sample of 100 of Valve A cracked under 4,500 psi. Six out of a random sample of 100 of Valve B cracked under 4,500 psi. Test at a 5% level of significance. Based on the p-value at the 5% significance level what is your conclusion? Op-value 0.025 so we reject the null hypothesis and conclude that there is enough evidence to say that there is a difference in pressure tolerances of Valve A and Valve B. Op-value 0.025 so we do not reject the null hypothesis and conclude that there is not enough evidence to say that there is a difference in pressure tolerances of Valve A and Valve B. Op-value > 0.05 so we reject the null hypothesis and conclude that there is enough evidence to say that there is a difference in pressure tolerances of Valve A and Valve B. Op-value

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