p1=x1/n1=40/45=0.8889 p2=x2/n2=0.8544 Pp= n1 n2 x1 x2 =0.8649 z= p p (1p p ) 1/n1 1/n2 p1p2 =0.56 thus using probability table P=P[z 0.56]=2p[z 0.05

p1=x1/n1=40/45=0.8889 p2=x2/n2=0.8544 Pp= n1 n2 x1 x2 =0.8649 z= p p (1p p ) 1/n1 1/n2 p1p2 =0.56 thus using probability table P=P[z<-0.56 or z>0.56]=2p[z<-0.56]=0.5754 since P=0.5754>0.05 Thus we fail to reject null hypothesis and thus we conclude that there is no sufficient evidence that echinacea has an effect on rhinovirus