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??????? [ P=4,000 int_{0}^{6} t e^{-0.1 t} d t ] with ( P ) in dollars and ( t ) in years. Find the present
??????? \[ P=4,000 \int_{0}^{6} t e^{-0.1 t} d t \] with \( P \) in dollars and \( t \) in years. Find the present value (in dollars). (Round your answer to the nearest cent.) 2 answers
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