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Page 21 of 25 Previous Next Given a non-standard normal random variable (X) with the mean 97 and standard deviation 23, find X = a
Page 21 of 25 Previous Next Given a non-standard normal random variable (X) with the mean 97 and standard deviation 23, find X = a when the area between 97 and a is 0.4589. Separate the answer with (,) Table for required value of : Done Table for areas under the standard normal curve X .00 01 .02 .03 05 06 07 .08 09 0.0 .0000 -0040 .0080 .0120 .0160 .0199 -0239 .0279 .0319 .0359 1.6 .4452 .4463 .4474 .4484 .4495 -4505 .4515 .4525 .4535 -4545 1.7 -4554 .4554 -4573 .4582 -4591 -4599 -4599 .4616 .4616 .4633Page 22 of 25 Previous Next Given a non-standard normal random variable (X) with the mean 92 and standard deviation 27, find X = a > 100, when the area between 92 and a is 0.3577. Table for required value of z Table for areas under the standard normal curve X .00 01 .02 03 .04 .05 06 07 .08 1.0 .3413 .3438 .3461 .3485 .3508 .3531 3554 .3577 3599 3621 1.5 4332 .4345 .4357 4370 .4382 .4394 -4406 4418 .4429 .4441 1.6 .4452 4463 .4474 .4484 4495 -4505 4515 4525 4535 .4545 1.7 4554 .4564 -4573 .4582 .4591 .4599 .4608 .4616 -4625 4633 1.8 .4641 .4649 .4656 4664 .4671 -4678 .4686 .4693 -4699 4706Previous Next Suppose the verbal SAT scores are normally distributed with a mean of 520 and a standard deviation of 70. If Andy's score is at the 90" percentile, what is his score? (Round the answer to the nearest whole number) Table for required value of Done Table for areas under the standard normal curve X .00 .01 .02 .03 04 .05 .06 .07 08 .09 0.0 .0040 .0040 .0080 1.0120 .0160 .0199 .0239 .0279 .0319 .0359 1.2 .3849 .3869 .3888 .3907 .3925 .3944 .3962 .3980 .3997 .4015Page 24 of 25 Previous Next GRE (Graduate Record Exam) scores are normally distributed with a mean of 1400 and a standard deviation of 160 [N(1400, 160)]. Above what GRE score will put you in the top 2% of all graduate applications? ( Round the answer to the nearest whole number). Table for required value of : Table for areas under the standard normal curve .00 01 .02 .03 .04 .05 .06 .07 08 0)9 0.0 1.0000 .0040 .0080 .0120 .0160 .0199 1.0239 .0279 .0319 .0359 1.4 .4192 .4207 .4222 .4236 .4251 .4265 4279 .4292 4306 .4319 1.7 4554 .4564 .4573 .4582 .4591 4599 4608 -4616 .4625 .4633 1.8 .4641 .4649 .4656 .4664 .4671 .4678 4686 .4693 4699 4706 2.0 .4772 .4778 .4783 .4788 .4793 .4798 4803 4808 .4812 .4817 2.3 4893 .4896 .4898 .4901 4904 .4906 .4909 .4911 .4913 4916Previous Next 50563Exp4 IQ examination scores of 600 members of a club are normally distributed with a mean Use me to enter the of 174 and standard deviation 14. How many of the members of the club have IQ scores 2 3 between 160 and 185. (Round the answer to the nearest whole number). 8 9 Table for required value of a Done Let X denote the IQ scores of the members of the club We are given 0 3413 0 2852 X ~ N(174, 14). The probability ( p) than Table for areas under the standard normal curve X .00 .01 .02 .03 .04 .05 .06 07 .08 09 IQ score between 160 and 185 is given 0.0 .0000 0040 .0080 .0120 .0160 0199 .0239 .0279 .0319 .0359 0.7 2580 .2611 .2642 .2673 .2704 .2734 .2764 .2794 .2823 .2852 p = P(160
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