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Part 1: Changing Current (L=3.2cm; current loop 39). Record the values. Current (A) Mass (g) 0.50 0.25 g 1.00 0.479 1.50 0.679 2.00 0.899
Part 1: Changing Current (L=3.2cm; current loop 39). Record the values. Current (A) Mass (g) 0.50 0.25 g 1.00 0.479 1.50 0.679 2.00 0.899 2.50 1.12 g 3.00 1.35g 3.50 1.559 4.00 1.77g 4.50 1.95g 5.00 2.17 Part 2: Changing Conductor Length (I = 2.00 A). Record the values. Current Conductor Mass (g) Loop Length (cm) 40 1.2 0.31 37 2.2 8.6 39 3.2 0.74 38 4.2 0.93 41 6.4 114 42 8.4 .2.06 FINAL DATA (Clean and legible) Part A: Changing Current (L=3.2cm; current loop 39) Current (A) 0.50 1.00 1.50 2.00 2.50 3.00 3.50 4.00 4.50 5.00 Slope PART A = Mass (kg) Part B: Changing Conductor Length (I = 2.00 A) (10 points) BPARTA = Current Loop Conductor Length (m) Mass (kg) Force (N) 40 37 39 38 41 42 Slope PART B = % difference in B = BPART B = Force (N) ANALYSIS PART A: 1. Plot a graph of force (vertical axis) versus current (horizontal axis). Inspection of the magnetic force formula predicts that the graph will be a straight line: F = ILB sin0-LB-1 (0-90'; sin-1) y m.x 2. Find the slope of the graph on the ORIGINAL DATA. According to the above formula, the slope m is equal to the product of the length of the wire L and the strength of the external field B. Divide the slope by the value of the length of the wire (in meters) to obtain a value for the magnetic field (in Tesla). Call this quantity BPART A- PART B: 1. Plot a graph of force (vertical axis) versus length (horizontal axis). Inspection of the magnetic force formula predicts that the graph will be a straight line: F = ILB sin 0 = IBL (0-90'; sin=1) m.x 2. Find the slope of the graph on the ORIGINAL DATA. According to the above formula, the slope m is equal to the product of the current in the wire I and the strength of the external field B. Divide the slope value of the current in the wire I to obtain a second value for the magnetic field (in Tesla). Call this quantity BPART B. 3. Compare the results from part A and part B by calculating the percent difference between the two values obtained for the magnetic field: % difference - BPART A+ BPART B B PART 100% 2 ORIGINAL DATA (clean and legible) Part 1: Changing Current (L-3.2cm; current loop 39). Record the values. Current (A) Mass (g) 0.50 0.25 1.00 0.47 1.50 0.67 2.00 0.89 2.50 1.12 3.00 1.35 3.50 1.55 4.00 1-77 4.50 1-95 5.00 2.17 Part 2: Changing Conductor Length (I = 2.00 A). Record the values. Current Loop Conductor Mass (g) Length (cm) 40 1.2 0.31 37 2.2 0.60 39 3.2 0.74 38 4.2 0.93 41 6.4 1.14 42 8.4 2.06
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