Part 1: Create a "Study Guide" that addresses each topic of the course. Include specific formulae and theory. The "Study Guide" should include the following topics. Basically summarize each unit with examples in a simple, but concise way: 1) Characteristics and Properties of Functions 4) Rational Functions, Equations and Inequalities 2) Polynomial Functions 5) Trig Functions and Identities 3) Polynomial Equations and Inequalities 6) Exponentials and Logarithmic Functions Your study guide MUST be created using technology. Feel free to make is as creative as possible. If you want to make a hand made drawn poster, that is also allowed. Part 2: With the study guide, include three unique (word problems) examples of your creation showing the concepts and theory in action (rubric below) from any four sections listed above 1) to 5). The examples must be fully solved and explained. Please see the example below. It shows what a fully solved and explained solution "does not" and "does" look like. Compare these two solutions from the grade 10 course. Examples:Examples: The length of one leg of a right triangle is This is the type of work you should be 7 cm more than that of the other leg. The submitting for Part 2: length of the hypotenuse is 3 cm more To solve this problem, we need to use the Pythagorean than double that of the shorter leg. Find Theorem. Our hypotenuse squared is equal to the sum of the the lengths of each of the three sides. squares of the other two sides. (2x + 3)2 = (x+7)2+x2 Now, since we are asked to find the value of x that will make 2x + 3 x +7 this true, we will need to expand and either solve the resulting quadratic by either factoring or using the quadratic formula. X We can use our special products to expand them. This is NOT what I am looking for: 4x2+ 12x +9 = x' + 14x + 49+xz 4x3+ 12x +9=x- + 14x + 49+x2 2x2 - 2x - 40 = 0 Collecting all terms on the left side of the equation: 2(x2 - x - 20) = 0 2x2 - 2x - 40 = 0 2(x - 5) (x + 4) = 0 2(x2 - x - 20) = 0 here we factor the GCF x = 5 or x = -4 2(x - 5)(x + 4) = 0 Factor the quadratic. (This shows little mathematical understanding Our roots will be x = 5 or x = -4 when each binomial is other than simply writing steps - easily copied) set to zero. Since side lengths must be positive, we must discard the negative root. Our only valid x value is 5. We can obtain these by substituting x = 5 into each expression for the side length to obtain lengths would be 5, 12, and 13. The solution on the right shows a deeper understanding of the steps required to solve the problem. A formal paragraph is not needed. Point form is fine, but it does need to flow and make sense. Note the length of the explanation. The expectation is that you are providing a very detailed explanation along with the algebra.You should create your own questions along with their solutions, with appropriate commentary with each problem. Don't forget that a well-chosen problem might display your understanding of numerous concepts. Create wisely