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Part 1 of 2 We must solve 125 = 75 + 110e(1/30)(In(15/22))t, or 5/11 5/11 =e(1/30)(In(15/22))t Part 2 of 2 Now, we have the
Part 1 of 2 We must solve 125 = 75 + 110e(1/30)(In(15/22))t, or 5/11 5/11 =e(1/30)(In(15/22))t Part 2 of 2 Now, we have the following. (Round your final answer to the nearest whole number. 30 (in (15)) = In 22 t = 30 In() == min
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Advanced Engineering Mathematics
Authors: Erwin Kreyszig
2nd Edition
471889415, 978-0471889410
