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Part 1 : Short Answer Problems 1 - 2 : A jar has 9 marbles ( 4 red and 5 blue ). Randomly selecting two
Part 1 : Short Answer Problems 1 - 2 : A jar has 9 marbles ( 4 red and 5 blue ). Randomly selecting two marbles. [ express answers as a fraction (reducing not required) ] (1) choosing with replacement: Pr( first = red , second = blue ) = 9 9 20 - 81 (2) without replacement: Pr( both are blue ) = Pr( 1st = blue , 2nd = blue ) C D Problems 3 - 4 : This is a frequency table of 10 items: A 3 4 B 1 2 (3) P( not C) = [ express answers as a fraction, decimal, or percent ] (4) Pr(D given A) Problems 5 - 6: From a group of 5 objects , we are choosing 3 (5) A city council with five members must appoint a (3-person) group consisting of a president, secretary and treasurer. How many of these executive groups are possible? For this problem, order matters. [ permutations ] (6) The debate club has five members, but only three can compete at the next meet. How many 3-person teams are possible ? For this problem, order doesn't matter. [ combinations ] (7) A 90% shooter in basketball successfully makes 9 out of 10 free throws. What is the probability that this shooter will make 80 shots in 90 tries? [ binomial formula: P(x) = (* )p*(1 -p)"-* (do not evaluate) ] P(A given B) = P(A and B) P(not A) = 1 -P(A) P(A or B) = P(A) + P(B) - P(A and B) P(B) m! m! mAr = m" mPr = mer = (m - r)! r! (m - r)
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