Part 3. Conservation of kinetic energy. Use the measured values from Part 2, table A, calculate kinetic energies and respective errors. Ki = K1i + K2i, Ki = K1 + K21, K = (1/2 ) mv 2 A. Results v = 0.1(m) / t (s), AK = Kf - Ki = Wnet, Subscript "i" - before collision Subscript "f" - after collision Kf. AK, tif, V1f, Kit, t2f , V2f, K2f, m1, m2, thi, V1i, K1i, tai, V2i, K2i, Ki, J S m/s J J J kg kg S m/s J S m/s J J S m/s - 159 m1=m2 2 217 . 14 8 0 . 217 0 O . 130 mi>m2 . 317 0 m1m2 317 1. 145 mi>mz 0 . 712 . 335 coupled .217 .217 . 174 B. Absolute errors of kinetic energy EAK = Eki + EKf, EKi = EK1i + EK2i , EKf = EKif + EK21 , EK = 2 Et K EK1i, EKzi, Eki, EKif , EK2f, Ekf, EAK, J J J J J J J m1=m2 m1>m2 m1m2 m1>m2 bulbs coupled