Part 3: Going Further. 1. How much higher would the skater have to be so that the skater had twice as much kinetic energy at the lowest point? Use the following calculations to prove your answer. Recall that m = 50 kg. Assume the skater starts from a height of 12 m, calculate... PE at the top = KE at the bottom = Your answer: 2. Assume the skater starts from a height of 12 m, calculate the speed ofskater at the bottom. 1 . (Because PE at top = KE at the bottom, mgh = E mvz. A rearrangement of the equation enables you to calculate the speed of skater at the bottom.) Show your work below. Height (m) Speed (m/s) Kinetic Energy (J) Potential Energy (J) Total Energy (J) 6 m (left) 0 0] 2940] 4 m (left) 3 m/s 225] 1960} 2185) 2 m (left) 4 m/s 400} 980] 1380] 0 m .5 m/s 6.25) O) 6.25) 2 m (right) 3 m/s 225) 980) 1205) 4 m (right) 4 m/s 400] 1960] 2360) 6 m (right) 0 01 2940]