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Part 3 of 4 Determine whether to reject Ho. Reject the null hypothesis Ho- Part: 3 / 4 Part 4 of 4 State a conclusion.
Part 3 of 4 Determine whether to reject Ho. Reject the null hypothesis Ho- Part: 3 / 4 Part 4 of 4 State a conclusion. There (Choose one) enough evidence to conclude that the mean number of hours per week spent on the Internet differs between 2010 and 2012 .More time on the Internet: A researcher polled a sample of 1012 adults in the year 2010 , asking them how many hours per week they spent on the Internet. The sample mean was 10.01 with a standard deviation of 13.90 . A second sample of 1011 adults was taken in the year 2012 . For this sample, the mean was 9.66 with a standard deviation of 13.81 . Assume these are simple random samples from populations of adults. Can you conclude that the mean number of hours per week spent on the Internet differs between 2010 and 2012 ? Let u, denote the mean number of hours spent on the Internet in 2010 . Use the a =0.05 level and the P-value method with the TI-84 calculator. Part: 0 / 4 Part 1 of 4 State the appropriate null and alternate hypotheses. H : H = H 0 0=0 0#0 H2 This is a two-tailed v test. X 5 Part: 1 / 4 Part 2 of 4 Compute the P-value. Round the answer to at least four decimal places. P= 1 Part: 2 / 4
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