Part 5 of 7 Ignoring the limit temporarily, we have -x-13x _ 1 -13x -b-13b _ 1 -136 4 1 -13 4 1 -13 13 169 13 169 13 169 The limit lim -b-13b has the form 0 . co and so requires L'Hospital's Rule. b - co 13 Using this, we have lim -b-13b -b = lim b - 0 13 b - co 13e136 L'H lim = b- 0