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Part A An object moves with simple harmonic motion of period T and amplitude A. During one complete cycle, for what length of time is
Part A An object moves with simple harmonic motion of period T and amplitude A. During one complete cycle, for what length of time is the position of the object greater than A /2? Express your answer in terms of T. AEd ? 2T t = 3 Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remainingI Review V Pal'lA A bunch ct grapes is placed in a spring scale at a supermarket. '( The grapes oscillate up and down with a period of 0.56 s, and the spring in the scale has a force constant 01 520 N/mt What '5 the mass 01 the grapes? Express your answer using two signicant llgures. D View Avallable Hlntls) m: 49 kg Previous Answers V Correct Picture the Problem: When a hunch at grapes are placed on the scale, they cause the spring to stretch beyond its equilibrium point' The grapes will then oscillate up and down on the spring with a period determined by their mass and the stiffness of the spring in the scale. Strategy: Substitute the spring force constant and the period into the period equation to solve for the unknown mass required to produce the measured period of oscillation Solution: Solve equation tor the period of a mass on a spring for the mass: T=21r=> m = 14%)? Substitute the numerical values: m = (620 N/m)( \"3: 5 )2: 4.9 kg Solution: Solve equation for the period of a mass on a spring for the mass: 2 Abunch of grapes is placed in a spring scale at a supermarket. T = 2771 p' % =:v m. = 34%) The grapes oscillate up and down with a period of 0.56 s, and the spring in the scale has a force constant of 529 me. Substitute the numerical values: 0.56 s h )2: 4.9 kg m. = (620 me V Part3 What is the weight of the grapes? Express your answer using two significant figures. I View Available Hlnt[s} V Part A A bunch of grapes is placed in a spring scale at a supermarket. The grapes oscillate up and down with a period of 0.56 s, and the spring in the scale has a force constant of 620 N/m. What is the mass of the grapes? Express your answer using two significant figures. View Available Hint(s) m = 4.9 kg Submit Previous Answers V Correct Picture the Problem: When a bunch of grapes are placed on the scale, they cause the spring to stretch beyond its equilibrium point. The grapes will then oscillate up and down on the spring with a period determined by their mass and the stiffness of the spring in the scale. Strategy: Substitute the spring force constant and the period into the period equation to solve for the unknown mass required to produce the measured period of oscillation. Solution: Solve equation for the period of a mass on a spring for the mass: T = 27\\ " = m=k(=) Substitute the numerical values: m = (620 N/m)(27 (0.56 s )2- 4.9 kgPart A Tsunami A tsunami traveling across deep water can have a speed of 750 km/h and a wavelength of 420 km . What is the frequency of such a wave? Express your answer in hertz. > View Available Hint(s) AEd ? f = Hz Submit
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