Part A: Centripetal Force . 445kg Mass of bob: 445, Radius of Revolution: 17 cm Time for 25 Revolution Period: 18.15/ 25= ,726 Revolutions: 18+ 13 5 Computed Centripetal Force: J 2 10 , 726 )2 Hanging Mass: 950 g = 0910 kg Directly Measured Centripetal Force: F, 2 m . g = (0. 950) (9, 83) = 9:31 M Computa Imputed Percent Difference: 15.67- 121 X100% = 64.2% COX (3, 67 ) Part B: Variation of Mass 17 cm Mass of bob: Radius of Revolution: (1 cu = all /m Time for 25 Revolution Period: 20, 36/25 = 0 .814 Revolutions: 20, 36 Computed Centripetal Force: Hanging Mass: Directly Measured Centripetal Force: Percent Difference:Part C: Variation of Radius Mass of bob: Radius of Revolution: Time for 25 22.5 em Revolutions: 13. 52 Revolution Period: Computed Centripetal Force: 12 Hanging Mass: 1330 g 230 Directly Measured Centripetal Force: 132 Percent Difference: D . Part C: Variation of Radius Mass of bob: 4 4 50 = 0. 4.Rg Radius of Revolution: 2. 25 m 22, 5cm = Time for 25 Revolutions: 34. 64 Revolution Period: 34 . 64 = 1. 386 25 Computed Centripetal Force: FC = 4 TT- ME _ 4 TT2 0. 4 45) ( 2. 25 ) ( 1 . 386) 2 Hanging Mass: 3 20 g Directly Measured Centripetal Force: Percent Difference: Part E: Swinging Ball Time for 25 Time per Revolutions: 24. 46 Revolution: Height of 19.5 cm Length of 3. 4 cm Height of String: 43 cm Ball: Hand: % Difference: Experimentally Theoretical using Determined Angle: Angle:PostLab Questions: 1) What are the major sources of error in this experiment? 2) How did your results change in Part B compared with Part A. Interpret this finding. Is this what you expect? Explain. 3) How did your results change in Part C compared with Part A. Interpret this finding. Is this what you expect? Explain. 4) Why did we not measure the mass of the ball for Part E? 5) The Earth has a mass of 5.97x10"kg and orbits the Sun in one year at an average distance of 1.496x10*km. What is the centripetal force, in Newtons, that keeps the Earth in its orbit around the Sun? 6) Explain your results for Part D