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Part A How much heat is required to convert 28.9g of liquid benzene (C_(6)H_(6)) at 51deg C to gaseous benzene at 100deg C ? The

Part A\ How much heat is required to convert

28.9g

of liquid benzene

(C_(6)H_(6))

at

51\\\\deg C

to gaseous benzene at

100\\\\deg C

? The boiling point of benzene is

80.1\\\\deg C

and

C_(m)[C_(6)H_(6)(l)]=136.0

(J)/(mol*\\\\deg C)

, and

\\\\Delta H_(vap )=30.72k(J)/(m)ol,C_(m)[C_(6)H_(6)(g)]=82.4(J)/(mol*\\\\deg C)

.\ Express your answer with the appropriate units.\

q=

\ Request Answer

image text in transcribed
Part A How much heat is required to convert 28.9g of liquid benzene (C6H6) at 51C to gaseous benzene at 100C ? The boiling point of benzene is 80.1C and Cm[C6H6(l)]=136.0 J/(molC), and Hvap=30.72kJ/mol,Cm[C6H6(g)]=82.4J/(molC)

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