Answered step by step
Verified Expert Solution
Question
1 Approved Answer
PART A - Sketch is not required, only correct values. Calculate the least-squares line. Putthe equation in the form of: 1?: a + bx. (Round
PART A - Sketch is not required, only correct values.
Calculate the least-squares line. Putthe equation in the form of: 1?: a + bx. (Round your answers to three decimal plaoes.) 9 = l:l + E x B Part [c] Find the oorrelation coefcient. {Round your answer It} tour decimal DIEDES.) Is it signicant? {Use a signicance level of [1.05.] C- Yes C- No El Part {d} Find the estimated maximum values for the restaurants on page ten and on page TD. [Round your answers to the nearest cent.) 8 Part [e] Does it appear that the restaurants giving the maximum value are placed in the beginning of the "Fine Dining" section? How did you arrive at vour answer? {3- Yes. there is a signicant linear correlation so it appears there is a relationship between the page and the amount of the discount. '3' No. there is not a Signicant linear correlation 30 it appears there is no relationship between the page and the amount oftne discount. 8 Part {1'} Suppose that there I.vere 200 pages of restaurants. What do you estimate to be the maximum value for a restaurant listed on page 200'? (Round your answer to the nearest cent} I: El Part to} Is the least squares line valid for page 200? Why or why not? 0 Yes. the line produced a valid response forthe maximum value. C- No, using the regression equation to predict the maximum value for page 200 is extrapolation. El Part {h} What is the slope of the least-squares (best-t) line? (Round your answer to three decimal places.) : Interpret the slope. As the page number increases by one page, the discount decreases by at :l. \fConstruct a 95% condence interval for the hue mean. Sketch the graph ottne situaljon. Label the point estimate and the lower and upper bounds of the condence interval. [Round your answers to two decimal places.)- 1?.?1 X 13.49 K The mean age of De Anza College students in a preyious term was 26.6 years old. An instructor thinks the mean age for online students is older than 26.6. She randomly surveys 58 online students and nds that the sample mean is 29.4 with a standard deviation of 2.1. Conduct a hypothesis test at the 5% level. Note: If you are using a Student's tdistribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must rst prove that assumption, though.)Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started