Part A The activation energy of a certain reaction is 30.8 kJ mol-. At 18 C, the rate constant is 0.0285 s-? At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer to 2 significant figures. T = Check Part B Given that the initial rate constant is 0.0285 sat an initial temperature of 18 C, what would the rate constant (in s-) be at a temperature of 255 C for the same reaction described in Part A? Express your answer with three significant figures. k= S? Check