Part A The electric field at a distance of 0. 131 m from the surface of a solid insulating sphere with radius 0.358 m is 1770 N/C. Assuming the sphere's charge is uniformly distributed, what is the charge density inside it? For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Field of a uniformly charged sphere. AEQ ? p= C/m3 Submit Request Answer V Part B Calculate the electric field inside the sphere at a distance of 0. 199 m from the center. AEQ 89 ? E= N/C Submit Request Answer Provide FeedbackPart A electric freed outside Sphere is R Y p Q ( R + 8 ) 2 R = radius 7 = distance from surface of Sphere Q = total change Inside Surface and AnGo 2 9x10' 1770 . gx10 ' ( 0.358 + 0-131 ) Q = 47.03 x10 C. change density, P= = 3Q 4 x R ] 4 x R 3 3 9 = 3 x 47. 03 x 10 9 An (0 - 358 ) 3 9 = 2.45 x 10 c / m 3Part B electric field inside solid sphere 3 6. 7 = 0 . 199 m E = 2- 45 x 10 X 0. 19 9 N / C 8. 2 5 X 10 72 E = 5 502 N/C