Part A The magnitude of the net force on the proton is , F = 1 X - Fy ( - 1 . 76 - 10 23 ) 2 + ( 2. 16 # 10 7 2 ) 2 F = 2 79- 10-13 N ( And] . Part B The force on the proton is in x-y plane . The direction of force with respect to positive x-axis in the . plane of the page is given by the angle o as, tano 2 fy 2.16 + 10-13 - 2.76* 10-13 . o2 tant ( 2.16 - 1. 76 02- 50. 83 CAUD) . The negative sign indicates that the direction of force is 50.83 " below the positive x anis .Part B What is the direction of the force on the proton in the figure? Express your answer using two significant figures. AEd 0 = 45 counterclockwise from the positive y-axis Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining Provide Feedback Figure X X E X + B