Part A The velocity of a particle traveling in a straight line is given by v = (6t - 3t?) m/s, where t is in seconds. Suppose that s = 0 when t = 0. Determine the particle's acceleration when t = 4.8 s. Express your answer to three significant figures and include the appropriate units. a= -22.8 9 Submit Previous Answers Correct Part B Determine the particle's position when t = 4.8 s. Express your answer to three significant figures and include the appropriate units. HA Value Units Submit Request AnswerSubmit Request Answer The velocity of a particle traveling in a straight line is given by v = (6t - 3t?) m/s, where t is in seconds. Suppose that s = 0 when t = 0. Part C How far has the particle traveled during the 4.8-s time interval? Express your answer to three significant figures and include the appropriate units. HA FOE ? STE Value Units Submit Request Answer V Part D What is the average speed of the particle for the time period given in previous part? Express your answer to three significant figures and include the appropriate units. HA ? Vavg Value Units Submit Request AnswerPart A The velocity of a particle traveling in a straight line is given by v = (6t - 3t?) m/s, where t is in seconds. Suppose that s = 0 when t = 0. Determine the particle's deceleration when t = 4.7 s. Express your answer to three significant figures and include the appropriate units. View Available Hint(s) a = Value Units Submit Part B Determine the particle's position when t = 4.7 s. Express your answer to three significant figures and include the appropriate units. View Available Hint(s) Value Units SubmitPart C The velocity of a particle traveling in a straight line is given by v = (6t - 3t?) m/s, where t is in seconds. Suppose that s = 0 when t = 0. How far has the particle traveled during the 4.7-s time interval? Express your answer to three significant figures and include the appropriate units. View Available Hint(s) HA ? STE Value Units Submit V Part D What is the average speed of the particle for the time period given in previous part? Express your answer to three significant figures and include the appropriate units. View Available Hint(s) 0 6: ? Vavg Value Units Submit11 June 8:11 AM Part-A Given velocity, v= ( At - 3 +2) m/s Now , Ve as dt 2= (6t - 3+2) Hanes S = S ( 6t - 3+ 2 ) + CI Ice = constant of integral gration ]. Hency S = 3 + 2 - t 3 + C 1 Now at t= 0 , s = 0 Hanky CI = 0 Hency S = 3+ 2 -6 3 . Now acceleration , as du = ( 6 - st )m / s2 Hency at t= 4.8 second , acceleration , a = 6 - ( 6 x 9 .8 ) 2 - 22-8 m/s2 . Part . B The particle position at 1= 4.8 second is S = 3X4. 82 - 4.83 2 5 = - 41.472 meter , Part - C Distance travelled in 4.8 second interval is , - So ( ot - 3+ 2 ) at + 1 5 " " ( et - 5+ 2 ) at / [ 3+ 2 -+3 Jo + / [3+2-+3]4:8 = 4+45- 472 = 49. 472 . m Port - D Henry average speed . = 49. 47 2 = 10.3067 m/s . 4 . 8Part-A Given velocity, v= (At - 3 + 2 ) m/s. Now , at 1 veas = ( 6t - 3+2) Hanes S = S ( 6t - 3+ 2 ) + CI [ ce = constant of inter gration ]. Hency S = 3 + 2 - t 3 + C , Now at t=o , s = 0 Hanky CI = 0 Hency s = 3t 2 -63 Now acceleration , as dy = ( 6 - st )m /s2 Hency at t= 407 second , deacceleration , = 6 - (6 * 9.7 ) 1 2 22. 2 m /s 2 Part . B The particle position at 1 = 4.7 second is S = 3X4. 72 - 4.73 >S = - 37 . 553 - meter , Part . C Distance travelled in 4.I second interval is, - Soude + fut vatl . - So (ot -3+ 2 ) at + / S , " " ( at - 5 + 2 ) 24 / = [ 3+ 2 -+3 ) + / [3+2-+3],4071 = 4+ 41: 5 53 45-553 Port - D Henry average speed . = 45-55 3 4. F - = 9.69213 . m/s .For calculating distance travelled I have -10- taken 072 limit and then 2-4-8 or 2 4 4.7 limit because beyond t= 2 sec t the velocity is negative . so I. have to make -10- the t= 2 to t = 4.8 or 4.7 interval displace ment positive . -20 -30