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Part A Two point charges, q1=2 MC and q2=5 /C are placed in vacuum. Each one experiences a 5.0 N electric force due to the

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Part A Two point charges, q1=2 MC and q2=5 /C are placed in vacuum. Each one experiences a 5.0 N electric force due to the other charge. If each of the charges is increased by a factor of 4 the electric force on each of them becomes O 1.3 N 50.0 N O 20.0 N O 80.0 N 0 0.3 N Submit Request Answer Provide FeedbackV PartA The charge on the square plates of a parallel-plate capacitor isQ. The distance between the plates is cl. The potential across the plates is maintained with constant voltage by a battery as the distance between the plates is reduces to d/G. The amount of charge on the plates is now equal to Part A In the circuit shown in the figure find the current through the 10 Ohm resistor. The emfs of the two batteries are E1=8 V and E2=4 V Note: depending on how you choose the directions of currents you may get a negative value. It does not necesarily mean that you made a mistake. Just use the magnitude (absolute value) of the current to choose your answer. 2.00 0 E1 a 3.00 Q 1.00 0 E2 4.00 0 b 10.00 0 O 0.24 A O 20.00 A 0.96 A O 1.44 A O 0.48 APart A Each plate of a parallel-plate air-filled capacitor has an area of 0.0010 m2, and the separation of the plates is 26 um . An electric field of 1.2.10 V/m is present between the plates. What is the surface charge density on the plates? (80=8.85.10-12C2/N.m2 O 5.3 MC/m2 O 2.5 JC/m2 10.6 MC/m2 O 21.2 MC/m2 O 64 HC/m2 Submit Request

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