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Part B 1 2 4 6 5 ). 0. 4 438 0. 3180 Q. 237. 2 Q. 2269 3 Q ( 3721 a 39 69

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Part B 1 2 4 6 5 ). 0. 4 438 0. 3180 Q. 237. 2 Q. 2269 3 Q ( 3721 a 39 69 0, 2011 0. 5300 0. 3013 0.5 700 0 . 4277 04 277. Q.6.3602 Q. 4 4.29 0. 420 ?Experiment 24: Clastic is Inclastic collission last 1 Inclashe .. . ...... Record :" M. G -oldof far 189 6 , M, + MZ = calculate = .......' Part 2 elastic My = glider + bure + flag - 191:59. . gicat Has . . .........".. 89 62 = 10CM ............. colalake 10 cm Part 1 Data; 1 1 ci) 0. 6272 03 5031 .......Q.5075 0. 4270 0. 4647 0. 3339 5 0. 5261CALCULATION AND ANALYSIS 1. For inelastic collisions, calculate the values of v,; and v, by dividing the length of the flag L by the time it took for the flag to pass through the photo-gate, T,, and T, and then calculate for all five of your trials. 2. Calculate the average (mean) of the five values , the deviation of each value, the uncertainty of the average (mean), and the percent uncertainty for the average (mean) using equations 0.1, 0.3, 0.6 and 0.7. 3. Compare your average value of with the accepted value of (mum,J . Calculate the percent error of your calculation using equation 0.2. Is the % error less than or greater than the % uncertainty? Does the experimental evidence support the conservation of momentum? 4. For ONE of your collisions, calculate the kinetic energy of m, before the collision and the kinetic energy of m, +m2 after the collision. Calculate the percentage of the initial kinetic energy lost in the collision, as shown in equation 4.9. 5. For each of the five elastic collisions studied, calculate the values of v 1;, 15 2; and vy by dividing the length of the flags L, and Ly by the time it took for the flag to pass through the photo-gate, Ti Tzis Tyf. and Ty Then calculate the value of 12flail for all five of your trials. 6. Calculate the average (mean) of your five values of '2+zil Ivil+vis , the deviation of each value, the uncertainty of the average (mean), and the percent uncertainty for the average (mean). 7. Compare your average value of '2+val Iviltwirl with the accepted value m . Calculate the percent error of your calculation using equation 0.2. Is the % error less than or greater than the % uncertainty? Does the experimental evidence support the conservation of momentum? 8. For ONE of your collisions, calculate the kinetic energy of the two masses before and after the collision, using the definition of the kinetic energy. Calculate the percentage of the initial kinetic energy lost in the collision, as shown in equation 4.9. 9. How does this compare with what happened in the inelastic collision?DATA Part A: Inelastic Collision m(g)= m my + mz L(m) = N. THi (s) I(s) 2 3 4 5 Part B: Elastic Collision mg) = m2g) = MI = m 2 L(m) = Lz(m) = N. Ili (s ) Iz (s) I1 (S ) Iz ( s ) 2 4 5 35Experiment 4: Conservation Laws in Collisions OBJECTIVES The conservation laws for linear momentum and energy state that the total momentum and energy of an isolated system remain constant. This is true at all times in the system, even if some momentum or energy is transferred from one component of the system to another. In this experiment, you measure the motion and mass of a system comprised of colliding objects and calculate the energy and momentum of the system before and after the collision. The objectives of this experiment are as follows: 1. To measure the motion of objects that undergo elastic and inelastic collisions 2. To calculate changes in energy and momentum in elastic and inelastic collisions . To test the conservation laws for linear momentum and energy THEORY A conservation law states that a measurable property of an isolated physical system does not change with time. Two conservation laws are particularly important: conservation of linear momentum and conservation of energy CONSERVATION OF LINEAR MOMENTUM The law of conservation of linear momentum states that in a system where the sum of external forces is zero, the total momentum of a system does not change. In a system composed of # objects, the total momentum is given by the vector sum shown in equation 4.1. Total Momentum p = >m,v, = m,v, + m,v, + ...+ m, vn (4.1) Here, m, and v, are the mass and velocity of object number , respectively. As the objects interact with one another, the individual velocities may change, but the total momentum p remains constant. In this experiment, you study collisions between two objects. Before the collision suppose one object has mass m, and is moving at velocity v, and the other object has mass m, and is moving at velocity v27 . After the collision their velocities are v, and v2 . The law of conservation of momentum predicts that the total momentum is the same before and after the collision, as shown in equation 4.2. Conservation of Momentum mv,; + m,V2; =my + myV2 (4.2) Velocities are vector quantities, with direction as well as magnitude. In this experiment they act along a straight line so they have components only along one axis. However velocity in one direction (e.g. to the right) must be taken as positive while a velocity in the opposite direction must be taken as negative

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