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Part C answer should be done like this Please. Calculus and Vectors MCV4U-A Lesson 2. page 13 ................ In the following table, you need to

Part C answer should be done like this Please.

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Calculus and Vectors MCV4U-A Lesson 2. page 13 ................ In the following table, you need to find the value of f(a.+ h) - f(@) for decreasing values of h to estimate the (ath) - a instantaneous rate of change: f(a + h) - 1(a) Value of h ath f(a + h) (a + h) - a 0.1 2.1 (2.1) = (2.1)' -2(2.1) + 1 ((a + h) -f(a) 6.061 -5 -9.261 - 4.2 + 1 (a + h)-as (2.1)- 2 = 6.061 1.061 0.1 10.61 0.01 2.01 5.100601 fla + h)- f(a) 5.100601 - 5 (a + h) -a (2.01) - 2 0.100601 0.01 = 10.0601 0.001 2.001 5.010006001 f(a + A) - ((a) 5,010006001 - 5 (a + h) -a (2.001) - 2 0.010006001 0.001 10.006001 You could continue to select smaller and smaller values for h, but how small is small enough? What you really want is to let h get closer and closer to zero, which can be expressed as the following limit statement. Simplify the denominator of the rate of change (a + h) - a = h to come up with the following definition

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