Question
Part Description Answer Save Status A. The calculation to find work from a to b is: (600kPa-120kPa)(.5m 3 -.2m 3 ) -(600kPa-120kPa)(.5m 3 -.2m 3
| Part | Description | Answer | Save | Status |
| A. | The calculation to find work from a to b is: (600kPa-120kPa)(.5m3-.2m3) -(600kPa-120kPa)(.5m3-.2m3) (600kPa)(.5m3-.2m3) -(600kPa)(.5m3-.2m3) (120kPa)(.5m3-.2m3) -(120kPa)(.5m3-.2m3) No calculation required. W = 0 | 8.33 pts.100% 14% try penalty | # tries: 0 | |
| B. | Using the figure from part A, the calculation to find work from b to c is: (600kPa-120kPa)(.5m3-.2m3) -(600kPa-120kPa)(.5m3-.2m3) (600kPa)(.5m3-.2m3) -(600kPa)(.5m3-.2m3) (120kPa)(.5m3-.2m3) -(120kPa)(.5m3-.2m3) No calculation required! W = 0 | 8.33 pts.100% 14% try penalty | # tries: 0 | |
| C. | Using the figure from part A, the calculation to find work from c to d is: (600kPa-120kPa)(.5m3-.2m3) -(600kPa-120kPa)(.5m3-.2m3) (600kPa)(.5m3-.2m3) -(600kPa)(.5m3-.2m3) (120kPa)(.5m3-.2m3) -(120kPa)(.5m3-.2m3) No calculation required. W = 0 | 8.33 pts.100% 14% try penalty | # tries: 0 | |
| D. | Using the figure from part A, the calculation to find work from d to a is: (600kPa-120kPa)(.5m3-.2m3) -(600kPa-120kPa)(.5m3-.2m3) (600kPa)(.5m3-.2m3) -(600kPa)(.5m3-.2m3) (120kPa)(.5m3-.2m3) -(120kPa)(.5m3-.2m3) No calculation required! W = 0 | 8.33 pts.100% 14% try penalty | # tries: 0 | |
| E. | Using the figure from part A, how would you calculate the net work? Force*distance area enclosed add up all the work from each process both 1 & 2 both 2 & 3 both 1 & 3 |
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Molecular Engineering Thermodynamics
Authors: Juan J. De Pablo, Jay D. Schieber
1st Edition
0521765625, 9780521765626
