Part2: An apparel company makes blue jeans and leather pants. Heights of adult women are approximately normally distributed with a mean of 64.5 inches and a standard deviation of 2.5 inches. 7. Use your TI to generate 30 data values representing women. MATH >PROB>6:randNorm(64.5, 2.5, 30) for the TI 83 or u = 64.5, o : 2.5, trials : 30 for the TI 84>STO>Ll>Enter. Next press STAT>2:SortA(>Ll >Enter. Now go to your list and write down the 30 data values. Round to 2 decimal places. 8. Use the STAT function of your calculator to find the sample mean and sample standard deviation for your generated data. Round to two decimal places. Mean Standard deviation Use these sample statistics (sample mean and sample standard deviation) when computing questions 9 though 1 1. 9. What percent of female adults are taller than 5 feet 6 inches? Show all work which includes what was entered into the calculator. 10. What percent of female adults are shorter than 5 feet 2 inches? Show all work which includes what was entered into the calculator. 11. What percent of female adult heights are between 60 inches and 56 inches? Show all work which includes what was entered into the calculator. 12. Compare your results for questions 9 through 11 to your generated data. Do you get the same results? How do the percentages compare? Answer in a complete sentence. Because of the high cost of leather, the company has decided they cannot protably make leather pants in all sizes. Use your calculator to nd the heights corresponding to the following percentages. These are the heights of the shortest and tallest females who can purchase leather pants from this company. Hint: Use the population summary statistics. 13. The bottom 13%. Show all work which includes what was entered into the calculator. 14. The upper 15%. Show all work which includes what was entered into the calculator. 15. Compare your results for questions 13 and 14 to your generated data. Do you get the same results? Are the heights similar? Answer in a complete sentence.