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. Performance at home = 1.2 . Performance away = 1 . S(diff) = 0.75 . Number of observations = 100 Q6.3) (5 points) Let's

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. Performance at home = 1.2 . Performance away = 1 . S(diff) = 0.75 . Number of observations = 100 Q6.3) (5 points) Let's say your p-value for this hypothesis test is 0.058. With 95% confidence level what conclusion can you derive

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