PLEASE ADD COMMENTS IN THE CODES, SO THAT I CAN UNDERSTAND AND EXPLAIN MY FACULTY. I WILL UPVOTE AFTER GETTING PROPER SOLVE. :) Question 1 Solve the following problems using Assembly_Language Code

At_first,_ask_the_user_to_input_5_alphabetic_characters_and_store_them_in_an_array_of_size five._Now_your_task_is_to_generate_a_random_number_from_0_to_9._Here,_if_the_generated random_number_is_odd,_then_print_the_number_first_then_the_5_characters_in_reverse_order. Otherwise,_print_the_number_first_and_then_the_characters_in_their_given_order.

To_generate_a_random_number_you_first_need_to_create_a_seed._You_store_a_4_digit_16-bit_decimal number_in_a_variable._The_summation_of_the_individual_digits_of_the_number_will_be_your_seed. You_have_to_do_this_in_a_procedure_called_generate_Seed. To_generate_the_random_number_simply_do,_"seed_modulus_10"_or_seed_%_10_which_will return_a_value_between_0_to_9._You_have_to_do_this_in_a_procedure_called_generate_Rand. Remember_that_after_printing_the_random_number,_the_characters_will_be_printed_in_the next_line_altogether_without_any_spacing.

Input Example 01: Please enter 5 alphabetic characters: a l i c e Suppose 1584 is the number that you stored in a variable Output Example 01: The random number is: 8 alice

Explanation: The_summation_of_the_individual_digits_of 1584 is 18 (1+5+8+4_=_18)._So,_your_seed_is 18. Therefore,_the_random_number_is_seed % 10 = 18 % 10 = 8. As 8 is_an_even_number,_so_print the_characters_together_in_the_given_order. And_you_have_to_do_this_in_2_procedures,_generate_Seed_and_generate_Rand

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Please try solve the problems using- Lea Mov Loop Add Sub Cmp Jge Jle

Do not use advanced level syntax. I have to Solve the problem in my Academic way.

Try not to use - CALL,PROC,RET,JZ and Macro msg and all other advanced level syntax.

• You must have "emu8086" software to run the code and use Assembly Language only.
• After solving the problems check outputs then COPY and PASTE the codes
• Please give a screenshot so that I can understand.
• Please solve all the three parts as they are in a single problem.
• Do not give any java or python codes use Assembly Language only.

Skeleton Code:

.MODEL SMALL

.STACK 100H

.DATA

.CODE

;EXIT TO DOS

MOV AX,4c00H

INT 2H

MAIN ENDP

END MAIN

ScreenShot of the "emu8086" Software:

Take time but give me proper answer. I will upvote after getting proper solution. Thank you.

Please do not give any codes that was solved by any other solver before. I am uploading again to get new codes. If I get any code that was solved before I will downvote. Please pass the question If you cannot solve, just do not give solution that was solved before. Please do not give any codes that was solved by any other solver before. I am uploading again to get new codes. If I get any code that was solved before I will downvote. Please pass the question If you cannot solve, just do not give solution that was solved before. A 1 emu8086 - assembler and microprocessor emulator 4.08 file edit bookmarks assembler emulator math ascii codes help +++ * E new open examples save compile emulate calculator convertor options help about GO model small ; We choose model small because we need less than 64kb of memory size 002 003 ; We are creating messages 004 original source co... 005 printmsg macro msg ntmag 006 ; Pushing general 698 Mov ah, 4ch ng to emulator: noname.exe_ n 007 push ax 999 int 21h 008 push bx 100 file math debug view external virtual devices virtual drive help 099 push cx 101 G10 push dx 102 ; Procedure to read a n 1 ID >> 311 LEA dx,msg ; Load: 103 readnum proc near regis 012 mov ah,09h ; Use Load reload step back single step run step delay ms: 0 104 push ax G13 int 21 h G14 ; Poping all regi: 166 push cx 105 push bx alled registers F490: 92 94 . L 015 pop dx F400:02 94 916 pop cx 107 push dx 108 mov num,00 AX 4C 85 F4200: FF 255 RES BIOS DI 017 popbx 109 r1: F4201: FF 255 RES INT 921h 018 popax 110 mov ah,01 h B8 | 00 | 09 F4202: CD 205 = I RET 019 end 111 int 21h F4203 : 21 033 ! ADD CBX + SI, AL 020 .data 112 cmp al,dh CX 00 00 | F4204: CF 207 1 ADD [BX + SI], AL 021 113 je r2 14205: GIG GIGIO NULL ADD [BX + SI], AL 022 msg1 db Gah,Odh," 114 mov CX, ax DX 00 05 F4206: 00 000 NULL ADD [BX + SI], AL 023 arr dw 3_dup> 115 and cx,00ffh +4207: 00 000 NULL ADD [BX + SI], AL 024 msg2 db Gah, Odh," 10 -.. av L. AL CS F499 F4208: 00 000 NULL ADD [BX + SI], AL 025 msg3 db Gah, odh," F4209: 00 900 NULL ADD [BX + SI), AL 926 ms.O4 dh fahadh" IP TAO: 00 00 00 000 NULL ADD [BX + SI), AL 022 SERI emulator screen (80x25 chars) 00 000 NULL ADD [BX + SIJ, AL 028 00 000 NULL ADD [BX + SI], AL 029 00 000 NULL ADD [BX + SI), AL 030 1st Input:4 00 000 NULL ADD [BX + SI], AL 031 2nd Input:5 90 000 NULL ADD [BX + SI], AL 032 3rd Input:6 00 000 NULL ADD [BX + SI], AL 033 go 900 NULL Sorted Array:4 5 6 034 ADD [BX + SI), AL 00 000 NULL Median: 5 035 ADD [BX + SIL, AL 90 000 NULL ADD [BX + SIT, AL 036 00 000 NULL ADD [BX + SI], AL 032 00 000 NULL 038 039 040 source reset aux Vars debug stack flags 041 042 043 044 045 046 G47 048 049 050 AV 1 line: 166