Please answer #4,5,6 and show work

Questions 4 through 6 pertain to the situation described below: A woman and her dog are out for a morning run to the river, which is located 4.70 km away. The woman runs at 2.30 m/s in a straight line. The dog is unleashed and runs at 4.00 m/s between his owner and the river until the woman reaches the river. (4) How long does it take for the woman to reach the river? (A) 34.1 min; (B) 33.2 min; (C) 32.3 min; (D) 31.4 min; (E) 30.5 min. (5) What is the total distance run by the dog? A 8.17 km; (B) 7.66 km; (C) 7.15 km; (D) 6.64 km; (E) 6.13 km. (6) How fast must the woman run to reduce the distance run by the dog by 20.0%? (A) 2.68 m/s; (B) 2.88 m/s; (C) 3.08 m/s; (D) 3.28 m/S; (E) 3.48 m/s. 4 VPOG = 4.00 M16 V = 2. 30 mis 1.70 km 470 0 m 4. 70 KM x 1 1000m = 4700 m d = ( 4 .0 0 ) ( 20 43 . 65 ) = 8.174 km d = vt 4700 - 2.30 t 2.30 2.30 6540 mF V (2043. 5m t= 2047.68 x 1min - 34.1min 60 8 2043. 6 2045. GM distance 11 74. 8 ( 4.00 mist 1174. 8 1174.8 1634. 8 Student Name: Page 3 of 6