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Please answer all I will thumbs up and write positive feedback. I will need to add a photo of the chart for 24-28 please request

Please answer all I will thumbs up and write positive feedback. I will need to add a photo of the chart for 24-28 please request additional information for 24-28 and I will add it in.

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$104.905 Questions 19-22 are related to the following Your company self-insures its fleet of cars against collisions. You need to estimate the mean repair costs per accident so that you can set aside enough money to cover these costs. The data for repair cost for a random sample of accidents is shown below. 2345 1870 760 1320 1370 2155 1965 2595 1970 1075 1950 1920 1305 2320 2125 2185 2305 2950 2050 2095 965 145S 2645 2790 1655 2025 2020 1830 1990 2170 2370 2055 2005 1990 2650 2285 1840 1940 1670 1540 1720 1640 1485 2305 1590 2690 1860 2135 19 The point estimate of the mean repair cost is, a $2,274 $2,179 $2,087 $1,999 20 The standard deviation of the sample data is, $484.52 $464.10 $444.54 $425.80 The margin of error for an interval estimate with a 95% level of confidence is, $129.08 $134.46 $140.06 $145.90 22 To obtain a margin of error of $65 with a 95% level of confidence, what is the minimum number of repair costs to be included in the sample? Use standard deviation from the sample data as the planning value. 131 146 162 180 23 A different interval estimate of the mean repair cost, using the sample size as the original sample, yielded the following 95% confidence interval. $1,864.91 $2,122.59 What was the sample standard deviation? $425.81 $417.46 $409.27 $401.25 Use the binary data in the worksheet tab LWP to answer Questions 24-28. In a random sample of undergraduate students were asked if they lived with their parents while attending IUPUI. This sample is used to build an interval estimate, with a 95% confidence level, for the proportion of all IUPUI undergraduate students who live with parents. 24 What is the point estimate of the population proportion? 0.495 0.510 0.526 0.542 25 The standard error of the sample proportion is, 0.0167 0.0174 0.0182 0.0189 26 The margin of error for the interval estimate is, 0.034 0.043 0.053 0.067 27 The interval estimate is, 0.448 0.636 0.475 0.609 0.494 0.590 0.508 0.576 28 To build an interval estimate such that 19 of every 20 such intervals would capture the population proportion within :3 percentage points from each sample proportion, what is the required minimum sample size? Use p in the previous question as the planning value. 1146 1102 1060 1019

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