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Please answer all I will upvote and respond with positive feedback. Questions 10-18 are related to the following information A population has a mean of

Please answer all I will upvote and respond with positive feedback.

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Questions 10-18 are related to the following information A population has a mean of 1505.77 and standard deviation of 269.35 0 A random sample of size n= 80 is selected from this population, The probability that the sample mean exceeds 1523 18, 0.2762 0.2938 0.3126 0.3325 The fraction of the means from samples of size that are below 1480 is 0.1618 0.1740 0.1871 0.2012 12 What fraction of the means from random samples of size 80 are within : 40 from the population mean? 0.8572 0.8328 0.8080 0.7845 The margin of error for the middle interval that captures 95% of the sample means from samples of size $8.59 56.83 55.13 53.47 The middle interval that captures 959% of the means from samples of size 80 is, 1458.57 1552.97 1455.55 1556.99 1452.35 1559.19 1448.94 1562 60 Suppose we double the sample size to n - 2 " 80 = 160. Regarding the impact of changing the sample size on the margin of sampling error, doubling the sample size, but keeping the error probability a at 5%%, would. Increase by 50% Decrease by 50% Decrease by 29% Decrease by 38% 16 If we kept n at 80 but reduced the error probability to a = 0.01, the margin of error would . Decrease by 20% Increase by 209% Increase by 24% Increase by 31% 17 The middle interval that captures 99% of all means from samples of size BO 1435.5 1576.0 1483.3 1578.2 ang 1431.1 1580.5 1428.8 1582.8 18 Now keep the error probability as a - 0.05. We want to build an interval which captures 95% of the sample means within #15 from the population mean. What is the minimum sample size that would yield such an interval? 338 931 1034 1149

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