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Power Goat Lawn Company uses two sizes of mowers to cut lawns. The smaller mowers have a 22-inch deck. The larger ones combine two of the 22- inch decks in a single mower. For each size of mower, Power Goat has a different production function, given by the rows of the following table. Output per Hour Capital Input (square feet) (# of 22" mowers) Labor Input Small Mowers 5000 1 1 Large Mowers 8000 2 1 On the following graph, use the orange points (square symbols) to plot the q=40,000 isoquant for the small mower production technology. Use the purple points (diamond symbols) to plot the q=40,000 isoquant for the large mower production technology. Plot the points in order from left to right. Line segments will connect automatically.(Hint: Labor and capital are perfect complements in production.) 15 14 -I- 13 12 Small Mower lsoquant q=40,000 11 . D g 10 E 9 Large Mower lsoquantq=40.000 Q a LIJ n. 7 _l E 6 n. 5 6 4 3 2 1 o 0123456789101112131415 LABOR PER PERIOD In order to mow 40,000 square meet with the small mower technology and no wasted inputs, this would require units of capital and units of labor. Similarly, for the large mower technology and no wasted inputs, mowing 40,000 square feet would require units of capital and units of labor. Hint: Do not round your answers. Suppose half of the 40,000 square-feet lawn is to be mowed using the small mower technology, and half of the lawn is to be mowed with the large- mower technology. Assuming no wasted inputs, this production mix would require units of capital and units of labor. Suppose one-fourth of the 40,000 square-feet lawn is to be mowed using the small mower technology, and three fourths of the lawn is to be mowed with the large-mower technology. Hint: Do not round your answers. Assuming no wasted inputs, this production mix would require units of capital and units of labor. Based on your calculations in this problem, use the green line (triangle symbols) to plot the q=40,000 isoquant on the following graph. Hint: The isoquant is a straight line. Also, assume that 40,000 square-feet is the most square feet that can be mowed using the combinations of k and I that you calculated in each previous part of the problem. (9 10 + q=40,000 isoquant CAPITAL PER PERIOD 4 5 6 7 8 9 10 LABOR PER PERIOD