Please answer ALL questions as this is very important.

Use this link to answer questions 1-3: https://www.compadre.org/Physlets/mechanics/prob4_12.cfm

1. A large 2000-kg truck and a small compact car collide head-on. Click on "play" to run the animation. Notice the values of the velocities below the figure.

Before the collision, the velocity of the truck is [ Select ] ["20 m/s to the right", "0", "20 m/s to the left", "-20 m/s to the right"] and the velocity of the car is [ Select ] ["20 m/s to the right", "0", "-20 m/s to the left", "20 m/s to the left"] .

2. (This is a continuation of the previous question.)

Before the collision, the net force on the truck is [ Select ] ["to the right", "0", "to the left"] and the net force on the car is [ Select ] ["to the right", "0", "to the left"] .

3. (This is a continuation of the previous question.)

During the collision, the force that the truck exerts on the car is [ Select ] ["equal in magnitude to", "greater in magnitude than", "smaller in magnitude than"] the force the car exerts on the truck.

After the collision, the net force on the truck-car system is [ Select ] ["5 newtown", "zero", "to the left", "to the right"] . You know this because [ Select ] ["they move to the right", "they move at a constant velocity", "their common final velocity is 5 m/s"] .

Use this link to answer questions 4-7: http://physics.bu.edu/~duffy/semester1/c05_twoblocks.html.

4 The two blocks in the figure are connected by a string. They are both accelerated to the right by a force applied to the second string, which is attached to the blue object. The green block weighs 6 N and the blue block weighs 5 N. Use either the "play" or "step" buttons to observe the blocks move to the right.

The acceleration of the blue block is:

a. the same as the acceleration of the green block.

b. smaller than the acceleration of the green block.

c. greater than the acceleration of the green block.

5. (This is a continuation of the previous question.)

On a piece of paper, draw the two blocks and the two strings. Label as T₂ the force applied by the hand to the right on the string attached to the blue block. Then, label as T₁ the magnitude of the tension force in the first string (the one between the blocks).

The force of tension, T₁, [ Select ] ["acts to the right", "cancels with the force on the blue block and does not act", "acts upward", "acts downward", "acts to the left"] on the green block. The force with magnitude T₁ [ Select ] ["acts to the left", "cancels with the force on the green block and does not act", "acts downward", "acts upward", "acts to the right"] on the blue block.

6. (This is a continuation of the previous question.)

Which force or forces act(s) on the blue block [ Select ] ["Only T1 acting to the left.", "Only T2 acting to the left", "Only T1 acting to the right.", "Only T2 acting to the right.", "T2 acting to the left and T1 acting to the right.", "T2 acting to the right and T1 acting to the left."]

Which force or forces act(s) on the green block? [ Select ] ["Only T1 acting to the right.", "Only T1 acting to the left.", "Both T1 and T2 acting to the right.", "Only T2 acting to the left.", "T2 acting to the right and T1 acting to the left.", "Only T2 acting to the right."]

7. (This is a continuation of the previous question.)

The force of tension T2 is [ Select ] ["greater than", "the same as", "smaller that"] the force of tension T1 because [ Select ] ["T2 accelerates both blocks, while T1 accelerates only the green block", "T1 cancels between the blocks and T2 is the only force left.", "T1 has to pull both blocks and T2 has to pull only the blue block.", "They are an action-reaction pair of forces."]

Use this link to answer questions 8-13: https://www.compadre.org/Physlets/mechanics/prob4_11.cfm

8. Read the explanation below the simulation and answer the questions below.

Click on to play theanimation. As the blue (hanging) object falls down under the influence of the force of gravity, it pulls a 1-kg cart along a horizontal table.

The force(s) that act(s) on the hanging object while it is falling is (are) [ Select ] ["only the tension in the string (up)", "the weight of the cart (horizontal), the weight of the blue object (down), and the tension in the string (up)", "the weight of the blue object (down) and the tension in the string (up)", "the weight of the cart (down), the weight of the blue object (down), and the tension in the string (up)", "only the weight of the blue object (down)"] .

The v_x vs. t graph shows the time dependence of the velocity [ Select ] ["for both the cart and the hanging (blue) object", "for the cart only", "for the pulley only", "for the hanging (blue) object only"] .

9. (This is a continuation of the previous question.)

During the motion, the cart [ Select ] ["has a constant, non-zero acceleration", "has a zero acceleration", "has a uniformly decreasing acceleration", "has a uniformly increasing acceleration"] , which is [ Select ] ["smaller than", "the same as", "greater than"] the acceleration of the hanging mass.

10. (This is a continuation of the previous question.)

Click on the v_x vs. t graph. A new graph will appear. Use the right-click mouse button to click on any point on the blue line on the graph. Read off the coordinates of that point that appear in the yellow rectangle. The first number is the time and the second is the velocity. Then, right-click on a different point on the blue line (the error will be reduced if the two points are as far away from each other as possible). Use the coordinates of the two points to calculate the "rise" and the "run" of the blue line. Calculate the slope of the line using: slope = rise/run = v₂ - v₁ / t₂ - t₁

The slope is about [ Select ] ["+3.3", "-3.3", "2.6", "+0.3", "-0.3", "-2.6"] and is equal to the system's [ Select ] ["velocity", "distance traveled", "The answer is not listed among the given choices.", "acceleration"] .

11. (This is a continuation of the previous question.)

Use the value of the slope you just found in the previous question, and a mass of the cart of 1 kg to calculate the net force on the cart. Notice that the net force on the cart is equal tothe tension (T) in the string that's pulling the cart.

So, the net force on the cart = tension is about:

a. 2.6 N

b. The answer is not listed among the given choices.

c. 0.3 N

d. 3.3 N

12. (This is a continuation of the previous question.)

The same force of tension that you found in the previous question, is also pulling up on the hanging mass, while its weight is pulling it down. If the mass of the hanging object is M, the tension in the string is T, and the acceleration due to gravity is g, then the net force on the hanging mass can be written as:

a. 0

b. Mg - T

c. Mg + T

d. T - Mg

13. (This is a continuation of the previous question.)

Use the formula you just got for the net force on the hanging mass and the values of the tension T in the string and the acceleration of the system you got previously to calculate the mass of the hanging object, M.

The mass M is about:

a. 3.3 kg

b. 0.51 kg

c. 1.97 kg

d. 1 kg