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Instructions: You will need adiditional shects of paper. Put your name on each shect and identify the question. Use the quick reference card to find the opcode, funct, and reginter nuaber as suggested below. 1. Derive the hex machine code for the following assembly language instructions, You mut show your work, i.e. the field names, followsd by a mapping of the assembly language statement into those fields (in binary), folloned by hexifying the resmit. Here is an example for the aswmbly language staterment add $t0, \$t. $2. (a) the Iu statement on textbook puge 71 (b) the 1b statement on page 64 of the-textbook (c) the s11 statement on textbook page 92 (d) the nor statement on textbook page 182 (e) the addi statement on page 195 of the textbook (f) the slt statement on page 94 of the textbook (g) the siti statement on page 136 of the textbook (b) the first su statement on page 134 of the textbook (i) the sb htatement on page 195 of the textbook (j) the second 1 ui statement on page 112 of the textbook (k) the bne statement on page 106 of the textbook; the target is four words past the bne statement, i.e., whatever statement is at the sum.exit label. Note: per textbook page 115 , the offset is relative to the following instruction, i.e. number of words from increnented PC value to target. (1) the j statement on page 195 of the textbook; note that the target is at word address 2500=0000009CA. Per texibook page 114. "...the 26-bit field in jump instruction is also a word address.." In this case. the value in the address field (2500) would correspond to the byte address 42500=10000. (w) the {r statement on page 64 of the textbook; note that we only noed a single source register, therefore the rt and rd fields are both set to szero. (n) the jal atatement on page 61 of the textbook: Again, per textbook pago H4, "..tho 26 -bit held in jump instruetions is abso a word addiress..." In this case. the value in the address field would correspond to a byte audresis 42500=10000