PLEASE ANSWER THE FOLLOWING ...............................

1)

1. Find the P-value for a left-tailed hypothesis test with a test statistic of z= -1.55. Decide whether to reject Upper H 0H0 if the level of significance is =0.10.

P-value =Round to four decimal places asneeded

2. A nutritionist claims that the mean tuna consumption by a person is 3.3 pounds per year. A sample of 60 people shows that the mean tuna consumption by a person is 3.1 pounds per year. Assume the population standard deviation is 1.06 pounds. At alphaequals=0.03, can you reject the claim?

Identify the standardized test statistic.

3. Find the critical value(s) for a left-tailed z-test with alphaequals=0.09. Include a graph with your answer.

The critical value(s) is(are) nothing.

(Round to two decimal places as needed. Use a comma to separate answers as needed.)

4. Test the claim about the population mean, u, at the given level of significance using the given sample statistics.

Claim: =50; =0.01; =3.94. Sample statistics: x=49.4, n=62

The standardized test statistic is

5. A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean monthly consumption of 910 kWh. Assume the population standard deviation is 123123 kWh. At alphaequals=0.01, can you support the claim? Complete parts (a) through (e).

Find the critical value(s) and identify the rejectionregion(s). Select the correct choice below and fill in the answer box within your choice. Use technology.

The critical values are plus or minus

The critical value is

6. Find the critical value(s) and rejection region(s) for the indicated t-test, level of significance , and sample size n.

Right-tailed test, =0.10, n=9

The critical value(s) is/are

Round to the nearest thousandth as needed. Use a comma to separate answers as

needed

2)

Find the P-value for a left-tailed hypothesis test with a test statistic of Z = 1.42. Decide whether to reject H0 if the level of significance is = 0.10.

P-value = (Round to four decimal places as needed.)

State your conclusion. Choose the correct answer below.

Since P , fail to reject H0.

Since P , reject H0.

Since P > , reject H0.

Since P > , fail to reject H0.

3)

Avandia is an anti-diabetic drug and, like all drugs, it can have side effects. One study of patients with congestive heart failure found that 5 of the 110 subjects randomly assigned to Avandia dies of a cardiovascular event during the duration of the study, compared with 4 of the 114 subjects assigned to the placebo. Is there evidence that patients with congestive heart failure have a higher probability of dying of a cardiovascular event if they take Avandia than if they take a placebo?

a.) State the null and alternative hypotheses.

b.) What is the P -value for this test?

c.) What is your conclusion? Reject H0 or Do not reject H0?

d.) Write a sentence describing your conclusion.

4)

1. Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to rejectH₀for the given level of significance.

Two-tailed test with test statistic z= -1.94 and= 0.07.

P-value = ?

2. Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject H₀for the given level of significance. Right-tailed test with test statistic z=1.74 and= 0.02.

P-value =?

3. Find the critical z values. Assume that the normal distribution applies.

Right-tailed test;= 0.01

z=?

4. Find the critical z values. Assume that the normal distribution applies.

Two-tailed test;= 0.06

z=?

5)

1)Find the chi-square values from chi-square distribution tables.

Please tell me exactly what to type into Excel to get these answers or if there are any formulas that could be used. Thank you

a)²_0.005with Sample Size = 101

b)²_0.10with Sample Size = 30

c)²_0.05with Sample Size = 16

d)²_0.995with Sample Size = 19

e)²_0.99with Sample Size = 96

6)

Find the value of the test statistic z using z =

.

1) The claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and the sample statistics include n = 800 deaths of the elderly with 15% of them attributable to residential falls.

Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).

2) With H1: p < 2/3, the test statistic is z = -1.89.

Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim.

7) In a clinical study of an allergy drug, 108 of the 202 subjects reported experiencing significant relief from their symptoms. At the 0.01 significance level, test the claim that more than half of all those using the drug experience relief.

7)

Find the test statistic,P-value, and critical value.Round to 3 decimal places.

Claim: The mean IQ score of statistics professors is greater than 118.

Sample data:n= 50,x= 120. Assume that?= 16 and the significance level is?= .05

test statistic

P-value

critical value

If you could show me how you get the answers, that would be great!

8)

1. The probability of selecting a sample containing n items from a population with N items without replacement in a Sampling Distribution is?

a)1/^NC_n

b)1/ⁿC_N

c)1/2ⁿ

d)1/2^N

2. Find the number of all possible samples from a population containing 18 items from which 6 items are selected at random without replacement.

a)18564

b)15864

c)20264

d)21564

3. A pack of cards contains 52 cards. A player selects 4 cards at random without replacement. Find all possible combinations of the cards selected.

a)207752

b)270752

c)270725

d)207725

4. A population contains N items out of which n items are selected with replacement. Find the probability of the sample being selected.

a)1/N

b)1/n^N

c)1/^NC_n

d)1/Nⁿ

5. A box contains 26 pairs of napkins. If 3 pairs of napkins are selected at random with a replacement then the number of possible samples is _______

a)17675

b)17566

c)17576

d)17556

6. A sample was formed consisting of 8 students from a total of 56 students for certain task. Find the sampling fraction of the population of students.

a)1/7

b)7

c)49

d)1/49

7. Find the population proportion p for an IPL team having total 30 players with 10 overseas players.

a)1/2

b)1/3

c)2/3

d)1/4

8. It is provided that for a sampling distribution E(X)=11 and =13. Find the bias in the sampling.

a)2

b)4

c)6

d)3

9. Find the standard error of population proportion p for sampling with replacement. The population proportion is 0.5 and size of sample is 4.

a)0.5

b)0.25

c)0.225

d)0.375

10. Find the value of standard error in a sampling distribution without replacement. Given that the standard deviation of the population of 100 items is 25.

a)3

b)4

c)2

d) 5

9)

1. Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.

n = 195, x = 162; 95% confidence

Select one:

a. 0.788 < p < 0.873

b. 0.789 < p < 0.873

c. 0.778 < p < 0.883

d. 0.777 < p < 0.884

2. Find the value of z/2 that corresponds to a confidence level of 91%.

Select one:

a. 1.645

b. 1.75

c. 1.34

d. 1.70

3. Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places.

98% confidence; the sample size is 800, of which 40% are successes

Select one:

a. 0.0404

b. 0.0339

c. 0.0446

d. 0.0355

4. 50 people are selected randomly from a certain population and it is found that 12 people in the sample are over 6 feet tall. What is the point estimate of the proportion of people in the population who are over 6 feet tall?

Select one:

a. 0.24

b. 0.18

c. 0.50

d. 0.76

5. Thirty randomly selected students took the calculus final. If the sample mean was 95 and the standard deviation was 6.6, construct a 99% confidence interval for the mean score of all students.

Select one:

a. 91.69 < < 98.31

b. 92.03 < < 97.97

c. 92.95 < < 97.05

d. 91.68 < < 98.32

6. Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.028; confidence level: 99%; and unknown

Select one:

a. 2223

b. 1116

c. 1939

d. 2115

7. Find the appropriate critical value for the following:

99% confidence level ; n = 17; is unknown; population appears to be normally distributed.

Select one:

a. z/2 = 2.583

b. z/2 = 2.567

c. t/2 = 2.898

d. t/2 = 2.921

8. Find the critical value 2R corresponding to a sample size of 19 and a confidence level of 99 percent if the test it two-tailed.

Select one:

a. 6.265

b. 37.156

c. 34.805

d. 7.015

9. Find the critical value 2L corresponding to a sample size of 19 and a confidence level of 99 percent if the test is two-tailed.

Select one:

a. 6.265

b. 34.805

c. 7.015

d. 37.156

10. To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s = 0.16. Find the 95% confidence interval for the population standard deviation .

Select one:

a. 0.12 < < 0.24

b. 0.15 < < 0.21

c. 0.11 < < 0.25

d. 0.13 < < 0.22

10)

A study was conducted to investigate the effectiveness of hypnotism is reducing pain. Results for randomly selected subjects are given in the accompanying table. The values are before and after hypnosis; the measurements are given in centimeters on a pain scale.

Subject

A

B

C

D

E

F

G

H

Before

6.6

6.5

9.0

10.3

11.3

8.1

6.3

11.6

After

6.8

2.4

7.4

8.5

8.1

6.1

3.4

2.0

A) Test the claim that the sensory measurements are lower after hypnotism.

B) Construct a 95% confidence interval for the mean "before-after" differences.

11)

QUESTION 1

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p: n = 195, x = 162; 95% confidence.

A.

0.778 < p < 0.883

B.

0.788 < p < 0.873

C.

0.777

D.

0.789

QUESTION 2

Find the value of z_/2that corresponds to a confidence level of 89.48%.

A.

1.62

B.

0.0526

C.

1.25

D.

-1.62

QUESTION 3

Find the critical value z_/2that corresponds to a 98% confidence level.

A.

2.33

B.

2.05

C.

1.96

D.

1.75

QUESTION 4

Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level: 98% confidence; the sample size is 800, of which 40% are successes.

A.

0.0404

B.

0.0446

C.

0.0339

D.

0.0355

QUESTION 5

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a 95% confidence interval for the true proportion of all medical students who plan to work in a rural community.

A.

0.0251 < p < 0.0854

B.

0.0280 < p < 0.0826

C.

0.0323 < p < 0.0782

D.

0.0360 < p < 0.0745

QUESTION 6

Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level: 95% confidence; n = 2388, x = 1672.

A.

0.0248

B.

0.0184

C.

0.0206

D.

0.0156

QUESTION 7

Use the given degree of confidence and sample data to construct a confidence interval for the population mean . Assume that the population has a normal distribution.

Thirty randomly selected students took the calculus final. If the sample mean was 95 and the standard deviation was 6.6, construct a 99% confidence interval for the mean score of all students.

A.

91.68 < < 98.32

B.

91.69 < < 98.31

C.

92.95<<97.05

D.

92.03<<97.97

QUESTION 8

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.

A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the 98% confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.

A.

0.301 < p < 0.445

B.

0.304 < p < 0.442

C.

0.308 < p < 0.438

D.

0.316 < p < 0.430

QUESTION 9

Use the given degree of confidence and sample data to construct a confidence interval for the population mean . Assume that the population has a normal distribution.

A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with s = 17.6 milligrams. Construct a 95% confidence interval for the true mean cholesterol content of all such eggs.

A.

175.9 mg < < 194.1 mg

B.

173.7 mg < < 196.3 mg

C.

173.8 mg < < 196.2 mg

D.

173.9 mg < < 196.1 mg

QUESTION 10

Use the given degree of confidence and sample data to construct a confidence interval for the population mean .

Assume that the population has a normal distribution: n = 30, xbar = 84.6, s = 10.5, 90% confidence.

A.

80.68 < < 88.52

B.

79.32 < < 89.88

C.

81.34 < < 87.86

D.

81.36 < < 87.84