please answer the following :)

One-way ANOVA One-way ANOVA Source of Sum of Degrees Mean of F-Statistic p-value F=3. 969134434 P=0. 0269762765 Variation Squares of Squares Factor Freedom df=2 Between SS=9775. 047619 9775.048 2 4887.524 3.96913 MS=4887. 52381 Groups 0.02698 Error Within 4 df=39 48023.989 39 1231.383 Groups11. Math-54 sections that are classified as Scheduled, Scheduled for Exams, or Flexible, were sampled to see if the means on a common final were different. A one-way Analysis of Variance (ANOVA) was performed on the collected data to determine if the null hypothesis (UScheduled = (Scheduled Exam = Flexible) should be rejected or not. The samples are normally distributed.c. (4 points) Explain how you reached this decision