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Please answer the question below. A bullet of mass 10.0 gram moving at a velocity of 393 m/s toward the right strikes an orange of
Please answer the question below.
A bullet of mass 10.0 gram moving at a velocity of 393 m/s toward the right strikes an orange of mass 90.0 gram. The bullet passes through the orange and in the process pulls out 10.0 grams of orange innards with it. Assuming that this collision is elastic (i.e., that no kinetic energy is lost), what is the velocity of the rest of the remaining 80 grams of orange? Include a +/- sign to indicate direction, with rightward motion being positive and leftward motion being negative. Hint: It is easiest to do this problem if you first shift to the center of mass frame of the orange & bullet, determine the velocities of both objects before and after the collision in that frame (assuming no kinetic energy is lost) and then shift back to the "lab" frame. If this seems like an odd question, it is actually a model for explaining why JFK's head went backwards when he was shot from behind by Lee Harvey Oswald in 1963. That movement spawned a generation of conspiracy theories, and to this day over 50% of Americans think there was a second shooter. You can see a demonstration of this effect in the show Penn & Teller's BS! at https://www.youtube.com/watch?v=yzyw7 AcHbuY Image size: s M L Max 10 Before 90 20 V ,' After 80Step by Step Solution
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