please answer them correctly and with the right numbers

1. [-I1 Points] DETAILS SERCP715.AE.O1. Example 15.1 The Forces in a Hydrogen Atom Goal Contrast the magnitudes of an electric force and a gravitational force. Problem The electron and proton of a hydrogen atom are separated (on the average) by a distance of about 5.30 x 10'11 m. Find the magnitudes of the electric force and the gravitational force that each particle exerts on the other, and the ratio of the electric force, Fe, to the gravitational force, F9. Strategy Solving this problem is just a matter of substituting known quantities into the two force laws and then finding the ratio. Solution Substitute |q1| = |q2| = e and the M3 distance into Coulomb's law to nd R' = k",' : (3-99 X 10\" C2 the electric force. ' N 4112) (1,6 x 10-19 C)2 {5.3x10'\" 1102 Substitute the masses and distance into Newton's law of gravity to nd - .. the gravitational force. , (0.11 x 10'31 kg) (1.6T _\\' Ill2' kg) (5.3 x 10'11 In)2 Find the ratio of the two forces. Remarks The gravitational force between the charged constituents of the atom is negligible compared with the electric force between them. The electric force is so strong, however, that any net charge on an object quickly attracts nearby opposite charges, neutralizing the object. As a result, gravity plays a greater role in the mechanics of moving objects in everyday life. Hints: Getting Started | I'm Stuck Find the magnitude of the electric force between two protons separated by one femtometer (10'15 m), approximately the distance between two protons in the nucleus of a helium atom, The answer may not appear large, but if not for the strong nuclear force, the two protons would fly apart at an initial acceleration of nearly 7 x 1028 m/sz! Example 15.2 May the Force Be Zero Goal Apply Coulomb's law in one dimension. Problem Three charges lie along the x-axis as in Figure 15.7. The positive charge q1 = 16 pC is at x = 3 m, and the positive charge q2 = 10 uC is at the origin. Where must a negative charge Q3 be placed on the X-axis so that the resultant electric force on it is zero? Figure 15.7 Three point charges are placed along the x-axis. The charge [:3 is negative, whereas ql and q2 are positive. If the resultant force on Q3 is zero, then the force F13 exerted by ql on q3 must be equal in magnitude and opposite the force F23 exerted by qz on Q3. Strategy If Q3 is to the right or left of the other two charges, then the net force on [:3 can't be zero, because then F13 and F23 act in the same direction. Consequently, q3 must lie between the other two charges. Write F 13 and F23 in terms of the unknown coordinate position x, sum them and set them equal to zero, solving for the unknown. The solution can be obtained with the quadratic formula. Solution Write the X-component of F13. F +A, (16 x 10" 'C) IQ'sI Iii - = J [3 In l )12 Write the X-component of F23. (10 x 10'6 C) |q3| F23; : _|l\"L' 2 .1' Set the sum equal to zero. A (15 x 10-\" c) If,\" A (10 x 10-\" C.) qul U (I [3 In m)? r .r2 _ Cancel ke, 10'5 and Q3 from the equation, and 10(3 - x)2 = 15X2 rearrange terms (explicit significant figures and units are temporarily suspended for clarity). Put this equation into standard quadratic form, 109 - 6x + X2) = 16x2 _, go - 60x + 10x2 = 16x2 ax2+bx+c=0. 6x2+60x-90=0 Apply the quadratic formula. 50 i \"3600 {4) {G} (00) 60 :t :3? I] .l" = : '2 6 1'2 Only the positive root makes sense. x = E m Remarks Notice that it was necessary to use physical reasoning to choose between the two possible answers for x. This is nearly always the case when quadratic equations are involved. Three charges lie along the x-axis. The positive charge q1 = 9.67 mi is at x = 1.53 m, and the negative charge q; = -3.89 pC is at the origin. Where must a positive charge [:3 be placed on the x-axis so that the resultant force on it is zero? Hints: Getting Started | I'm Stuck 3. [-/1 Points] DETAILS SERCP7 15.P.001.SOLN. A charge of 3.70 x 1079 C is located 3.8 m from a charge of -2.80 x 1079 C. Find the magnitude of the electrostatic force exerted by one charge on the other. N4. [11 Points] DETAILS SERCP7 15.P.010. Calculate the magnitude and direction of the Coulomb force on each of the three charges shown in Figure P15.10. Figure P15.10 6.00 AM: charge Magnitude E NDirection 0 toward the left 0 toward the right 1.50 AuC charge Magnitude E NDirection 0 toward the left 0 toward the right -2.00 Auc charge Magnitude E NDirection 0 toward the left 0 toward the right 5. [l1 Points] DETAILS SERCP7 15.P.011. Three charges are arranged as shown in Figure P15.11. Find the magnitude and direction of the electrostatic force on the charge at the origin. N (magnitude) (counterclockwise from +x axis is positive) 3" !I On nl". n 'EDI'I "I (ill) Ill: 31,0!) nf'. Figure P15.1 1 6. [I1 Points] SERCP715.P.O18. (a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in Figure P15.10. S we Figure P15.10 (b) If a charge of -2.70 uc is placed at this point, what are the magnitude and direction of the force on it? Magnitude \\:| NDirection 0 toward the right 0 toward the left 7. [-/1 Points] DETAILS SERCP7 15.P.027. In Figure P15.27, determine the point (other than infinity) at which the total electric field is zero. m to the left of -2.5 x 10-6 C charge 1.0 m -2.5 uC 6.0 HC Figure P15.278. [11 Points] DETAILS SERESSEN1 15.P.037. Three point charges are aligned along the x axis as shown in Figure P15.49. Find the electric field at the position x = +1.? m, y = 0. Magnitude E N/CDirection O The field is in the +x direction. 0 The field is in the -x direction. 0 The field is in the +y direction. 0 The field is in the -y direction. 0 There is no eld at the position x = +1.7 rn, y = D. .' - U) nC Figure P15.49 A small m = 2.00 g plastic ball is suspended by a L = 17.0 cm long string in a uniform electric field, as shown in Figure P15.50. If the ball is in equilibrium when the string makes a 20.0 angle with the vertical as indicated, what is the net charge on the ball? HC E = 1.00 x 105 N/C L Figure P15.50