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please answer this ASAP The information in the question has error. There are CO2 = 20 % and CO = 10%. Q2 Carbon Dioxide (CO2)
please answer this ASAP
The information in the question has error. There are CO2 = 20 % and CO = 10%.
Q2 Carbon Dioxide (CO2) in air mixture need to be removed by using absorber. The solvent used is ultrapure water. The CO2-air mixture flow inside the absorber packed column with flowrate of 80 mol/min with 70 mol% CO2 and the rest is air. The solvent flowrate is 180 cm/min. The outlet stream consists of solvent with carbon dioxide that have been absorbed from air and another stream is air with the remaining of the carbon dioxide. From 10 am to 10 pm, the amount of carbon dioxide that managed to be absorbed in water is 640x10 cm which is 80mol%. (Density: Water: 1 g/cm', CO2: 0.00198 g/cm) (MW: Water: 18 g/mol, CO2: 44 g/mol) (a) Sketch and label in detail the process, including the unknown and equipment involved for the above statement (6 marks) (b) (c) Calculate all unknown stream variables in (mol/min). (17 marks) The mol fraction of carbon dioxide removal from air is monitored and found to have the value mentioned in the statement mentioned above. After 10 pm, it begins to have constant reading. Predict the most likely causes of the constant reading. (2 marks)Step by Step Solution
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