please answer with all steps:

Find the slope of the tangent line to the curve defined by 3x2 + xy + 4y = 261 at the point (-1, -2). The slope of the curve at the point (-1, -2) isIf 3x2 + 5x + xy = 5 and y(5) = -19, find y' (5) by implicit differentiation. y'(5) = Thus an equation of the tangent line to the graph at the point (5, -19) is y =Use implicit differentiation to find an equation of the tangent line to the curve 3:93 + 5mg : 36 at the point (6, 1). The egyatidn C] defines the tangent line to the curve at the point (6, 1)