Please Calculate S(Q)= integral of p(r)e^(-iQ*r) d^3r for the diffraction from a 3D crystal thin film with an arbitrary thickness "t" and p0=1. While doing so, calculate p(x),p(y), p(z), and simplify using [(e^itheta - e^-itheta)/2i] = sintheta and using L'Hopitals Rule to show that S(Qz) = tsinc[Qzt/2].

Use the slides provide as guidance to derive the answer.

Diffraction from a 2D crystal of thickness "(" p ( 2 ) = 1 12Ist Qz Real space Z sin (O_t/2) PK) = S(laver) (Q) = 6(Q )x(") -10,1/2 Q./2 Ply ] = PIX )Diffraction from a 2D crystal of thickness "(" Real space QZ Xo_ Q1 Z S(laver) (Q) = 6(Q )xo (m) sin (Q_1/2) -10.1/2 0./2 5 CQXI Quip 2 .iQx C JZ eax edy - Do