Please check my homework. Thank you

Ques. 1. Given:

Network Address: 192.168.42.0

Minimum number of usable hosts needed in each subnet (while maximizing the number

of subnets in the network) = 28

Find the following:

a) Address Class: C

b) Default subnet mask (decimal): 255.255.255.0

c) Default subnet mask (binary): 11111111.11111111.11111111.0

d) Number of bits borrowed: 3

e) Custom Subnet mask (binary): 11111111.11111111.11111111.11100000

f) Custom Subnet mask (decimal): 255.255.255.224

g) CIDR Notation : ?

h) Total number of subnets: 2^3 = 8

i) Number of hosts addresses in each subnet: 128 + 64 + 32 = 224

j) Number of usable hosts required in each subnet: 2^5 = 32

k) Number of usable hosts available in each subnet: 2^5 = 32 - 2 = 30

l) Address ranges (Network Address, Usable Host Range, Broadcast Address)

192.168.42.0 / 192.168.42.1 - 192.168.42.30 / 192.168.42.31

192.168.42.32 / 192.168.42.33 - 192.168.42.62 / 192.168.42.63

192.168.42.64 / 192.168.42.65 -192.168.42.94 / 192.168.42.95

192.168.42.96 / 192.168.42.97 - 192.168.42.126 / 192.168.42.127

192.168.42.128 / 192.168.42.129 - 192.168.42.158 / 192.168.42.159

192.168.42.160 / 192.168.42.161 - 192.168.42.190 / 192.168.42.191

192.168.42.192 / 192.168.42.193 - 192.168.42.222 / 192.168.42.223

192.168.42.224 / 192.168.42.225 - 192.168.42.254 / 192.168.42.255