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please clearly solve. thank you 6. An auto-parts producer is considering buying a new material handling system which has a purchase price of $170,000, a
please clearly solve. thank you
6. An auto-parts producer is considering buying a new material handling system which has a purchase price of $170,000, a useful life and MACRS class life of 5 years, and a salvage value of $10,000. The system will allow the company to save an amount of $100,000 each year due to a lower use of electric power and labor. The company has a tax rate of 35%. The initial investment will be financed with 30% equity and 70% debt. The interest rate on both short-term and long-term financing is 13% and the loan is to be repaid in equal annual amounts over the project life. Click the icon to view the MACRS depreciation schedules. Click the icon to view the interest factors for discrete compounding when i= 13% per year. Click the icon to view the interest factors for discrete compounding when i = 21% per year. 8 (a) Prepare income and cashflow statements in table format and determine the after-tax cash flows below. (Round to the nearest dollar.) Period Net Cash Flow $ 1 $ 2 3 4 $ 5 (b) Under a MARR of 21%, the net present worth of the project is $ (Round to the nearest dollar.) Therefore, the project (1) be accepted. (c) The internal rate of return (IRR) of the project is 1% (Round to two decimal places. Therefore, it (2) be accepted 7: More Info 10: Class 3 7 10 15 20 Yearn Depreciation rate 200% 200% 200% 200% 150% 150% 33.33 44.45 20.00 32.00 5.00 14.29 24.49 3.750 2 10.00 18.00 9.50 7.219 3 14.81" 19.20 17.49 14.40 8.55 6.677 4 7.41 11.52 12.49 11.52 7.70 6.177 11.52 9.22 6.93 5.713 8.93 8.92 6 5.76 7.37 6.23 5.285 7 8.93 4.888 5.90 5.90 8 4.46 4.522 9 6.55 6.55 6.58 6.55 3.28 5.91 10 5.90 4.462 4.461 4.482 11 5.91 12 5.90 4.481 13 5.91 4.462 14 4.481 5.90 5.91 4.482 15 2.95 16 4.462 4.462 19 2.231 21 E 21 Year to switch from declining balance to straight line 2.231 8: More Info Single Payment Compound Present Amount Worth Factor Factor (F/P, i, N) (P/F, i, N) 1.1300 0.8850 Compound Amount Factor (F/A, 1, N) 1.0000 Equal Payment Series Sinking Present Fund Worth Factor Factor (A/F, I, N) (P/A, i, N) 1.0000 0.8850 Capital Recovery Factor (A/P, 1, N) 1.1300 1 2 1.2769 z = Nm 0.7831 2.1300 0.4695 1.6681 0.5995 1.4429 0.6931 3.4069 0.2935 2.3612 0.4235 1.6305 0.6133 4.8498 0.2062 2.9745 5 0.3362 1.8424 0.5428 6.4803 0.1543 3.5172 0.2843 2.0820 0.4803 8.3227 0.1202 3.9975 0.2502 2.3526 0.4251 co 10.4047 0.0961 4.4226 0.2261 8 2.6584 0.3762 12.7573 0.0784 4.7988 0.2084 3.0040 0.3329 15.4157 0.0649 5.1317 0.1949 10 3.3946 0.2946 18.4197 0.0543 5.4262 0.1843 9: More Info Single Payment Compound Present Amount Worth Factor Factor (FP, i, N) (P/F, i, N) 1.2100 0.8264 Compound Amount Factor (F/A, i, N) 1.0000 Equal Payment Series Sinking Present Fund Worth Factor Factor (A/F, i, N) (P/A, I, N) 1.0000 0.8264 N Capital Recovery Factor (A/P, 1, N) 1.2100 2 1.4641 0.6830 2.2100 2 min 0.4525 1.5095 0.6625 1.7716 0.5645 3.6741 0.2722 2.0739 0.4822 2.1436 0.4665 5.4457 0.1836 2.5404 0.3936 5 2.5937 0.3855 7.5892 0.1318 2.9260 0.3418 3.1384 0.3186 10.1830 0.0982 3.2446 0.3082 7 3.7975 0.2633 13.3214 0.0751 3.5079 0.2851 oooo e o 4.5950 0.2176 17.1189 0.0584 3.7256 0.2684 5.5599 0.1799 21.7139 0.0461 3.9054 0.2561 10 6.7275 0.1486 27 2738 0.0367 4.0541 0.2467 (1) O should (2) should should not should notStep by Step Solution
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