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Please compute these using JMP. Thank you! In a pilot study for testing the truth to the conventional wisdom that, on average, U.S. adults gain

Please compute these using JMP. Thank you! In a pilot study for testing the "truth" to the conventional wisdom that, on average, U.S. adults gain weight between Thanksgiving and January, a research team looked at responses from 8 randomly selected U.S. adults. The subjects were weighed (lb) on the day before Thanksgiving and again on January 3rdThe raw data are found in Table 1. The researchers suspect that U.S. adults gain weight on average, but are open to the possibility that conventional wisdom is backwards and they actually tend to lose weight.

Pre-Thanksgiving 163.9 157.3 163.5 161.9 159.6 156.8 160.9 162.6
Jan. 3rd 163.0 168.4 164.4 165.9 170.5 166.7 164.4 162.1
Diff
Compute the differences as Jan. 3 minus PreThanksgiving.If WebAssign marks your values wrong, read the previous sentence.

a. Fill in the missing table cells for the weight differences per the directions outlined in the bottom caption. b. The researchers want to know if the data provide strong evidence that, on average, U.S. adults' weight changes between Thanksgiving and January. The appropriate null hypothesis for this study is: (you have two attempts at this question)

H0:xdifference= 0H0:Jan 3rd-Thanksgiving= 0 H0:difference= 0H0:xJan 3rd+xThanksgiving= 0H0:Jan 3rd+Thanksgiving= 0H0:xJan 3rd-xThanksgiving= 0

c. The test statistic for this data set is: Round your answer to 4 decimal places. d. The p-value for this study is: Round your answer to 4 decimal places. e. Based on this we: (you have two attempts at this question)

Reject H0because the p-value is less than zero

Fail to reject H0because the p-value is less than zero

Reject H0because the p-value is greater than zero

Fail to reject H0because the p-value is greater than zero

Reject H0because the p-value is less than 0.05

Fail to reject H0because the p-value is less than 0.05

Reject H0because the p-value is greater than 0.05

Fail to reject H0because the p-value is greater than 0.05

f. Even if we hadn't calculated a 95% CI, we know from the p-value that: (you have two attempts at this question)

The 95% CI *must* contain the p-value, because we rejected H0

The 95% CI *must not* contain the p-value, because we rejected H0

The 95% CI *must* contain the p-value, because we failed to reject H0

The 95% CI *must not* contain the p-value, because we failed to reject H0

The 95% CI *must* contain zero, because we rejected H0The 95% CI *must not* contain zero, because we rejected H0

The 95% CI *must* contain zero, because we failed to reject H0

The 95% CI *must not* contain zero, because we failed to reject H0

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