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Please derive the (3.54) equation from the first-order reversible reaction, (53a,b). AR ,k1 AR ,k2 -dCA/dt=k1CA-k2CR ln(1XAeXA)=lnCA0CAeCACAe=M+XAeM+1k1t Ak2k1R,KC=K=equilibriumconstant Starting with a concentration ratio M=CR0/CA0 the

Please derive the (3.54) equation from the first-order reversible reaction, (53a,b). AR ,k1 AR ,k2 -dCA/dt=k1CA-k2CR
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ln(1XAeXA)=lnCA0CAeCACAe=M+XAeM+1k1t Ak2k1R,KC=K=equilibriumconstant Starting with a concentration ratio M=CR0/CA0 the rate equation is dtdCR=dtdCA=CA0dtdXA=k1CAk2CR=k1(CA0CA0XA)k2(MCA0+CA0XA)

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