Please do help me with this Physics subject assignments please. It is already been answered, and i only want thorough explanation in each equations or each numbers. Explanation on the solution part, the formula and how did i get the answer. Please do help me. I promise to give a full star rating, please...

3. A large wooden turntable in the shape of a flat uniform disk has a radius of 2.00 m an I,W, = J 2 W2 b. 14 - 1 I, WIZ I, = Mr2 30.5 ( 240 ) ( 3) 2 2 = 120 ( 2 ) 7 2 = 240 kgm 14 = 3 ( 240) (3)2 2 + mr 2- 520 kqm 2 KI = 10ROJ a. W= = 240 ( 3) = 1.31 rack Iz 520 2/2") Calculate the KeFF in a. b. C Q. F = -kx - Xk= = x (h, + k=) F = 5+Fa -xk= -x (k, +k.) F = F. + F - Kx - -kixit - kate K = ki + K 1 - Kx = =KIXI - KEXL Kerr . K, + K= b. The displacement ( x ) is also came on (or ) and forces may be different . F- -Kx - XK = - x (k,+Vz) F = F 1 +F. K - Ki+ k 2 -kx - - Kix, + kaxe Kerr . k.+ K2 -Kx =-K, XI -Vix1 C. . X XI+ X 2 E -K. - V1 K . . F- - Kx X - XI+X2 = Kerr = kitkz KI + KZ d. fi - 7 Tam 12 = fz = 7 + 573. )a.Given : m = 0.02 kg 15 5 W= 21 2" = 4.1 rods" A = 0.24 m T = 1.5s x = A cos ( wt - 0) X = (0.24 m) cos (4.2 rad s' x 05s-0) = (0 . 24 mm) cos ( 4.2 rad 5' x 0.5 5 - 0) A = Asin (0) (7 = cos" (1 ) = - 0. 01 m = Orad b. F = may = - kx - wm A * [sin ( we - 8 ) ] W - K or ken " - w' m A cos ( wt - 2 ) - wmx F = max - (4.2 rod - ) x 0.02 kg x - 0.121 m .m dly = 0. 043N - m 12 are [ Aces ( wt - 0 ) ] - MA i {cos ( wt - 0) 3] C. X = A cos (wt - p) - 0. 180 m = (0-24 m) cos ( 4.2 rod s' x t-0) t = 1 Cos " -D. 18 m 4.2 rads" 6-24 m = 0.585 d. Vx = + K VA'-x = + (4.2 rads' ) Jco-24m)= - (0-18m)2 = $ 0. 67 ms-1Assignment no. 6 J-X,+ x2 : Q.2 m ( 2 ) ( 0 -15 ) ! ( 4 ) ( 6.05 ) 2. ) K1 = 2. 00 N/m 3.0x24x2 = 62m 0.3 = 0.3 9. Kq = 6.00 N / m 3.0x1ty = 0.am 0 -3 = 0.3 M = 0. 100 kq 4x1 = 02 F1 = F1 Atm = 6.2m 4 4 X2 = 6.05 m KIX, = K2 X2 X2 = 0 . 05 m ( 2 - ON /m ) x1 = ( 6. DN/ m ) X z X 1 =3 (0-05) ( 2. D N ) m ) XL XI = ( 6. 0 N / m ) X z X - 0. 15 m (2.90/ m ) X 1 ( 2.0 1/m ) X1 = 30 x2 EQ 1 b. T = 20 m K EK = K, tka = KEFF = 2.00 N/m + 6:00 NIM T = 271 6-100 kg V 8. OD N/m KEPT = 8.00 N/M T - 5 10 10 = 0.+02