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please explain 3) (15 pts) An inverted cone creates the tank pictured below The tank has a height of 12 meters (m) and a base

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3) (15 pts) An inverted cone creates the tank pictured below The tank has a height of 12 meters (m) and a base diameter of 10 m. The tank starts with a depth of I'm of water. Set up, but do NOT evaluate, the integral needed to determine the work W/ required to pump water over the top edge until the depth of the water remaining is 1 m. Assume the gravitational constant g - 9.8m/s- and water density p = 1000 kgym 10 meter base diameter 12 meter " height Initial water I depth 9 meters

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