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Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marble with a diameter of 1.4 cm. How does the result compare to the actual circumference of 4.4 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball Diameter 7.3 23.6 4.3 21.7 6.9 4.0 21.2 Circumference 22.9 74.1 13.5 68.2 21.7 12.6 66.6 Click the icon to view the critical values of the Pearson correlation coefficient r. Critical Values of the Pearson Correlation Co Critical Values of the Pearson Correlation Coeffic The regression equation is y =+x ( = 0.05 a = 0.01 (Round to five decimal places as needed.) 0.950 0.990 a 0.878 0.959 0.811 0.917 gr 0.754 0.875 8 0.707 0.834 9 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0 708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 Help me solve this View an example Get more help - 40 0.312 0.402 45 0 294 0 378