Please give the solution in C language only and attach the output screenshot

Q23.1 Our institute decided to split the students into four groups to conduct an event. The procedure

for splitting is as follows:

h(A) = (Sum of ASCII value of the characters in the first name of A + age of A) % 4, where

A represents a student.

Eg:- h(Veena) = (86+101+101+110+97+19) % 4 = 2; where, 86 - ASCII(V), 101 - ASCII(e),

110 - ASCII(n), 97 - ASCII(a), 19 - age(Veena).

If h(A) =0, the student is placed in group 0; if h(A) = 1, the student is placed in group 1; if h(A)

= 2, the student is placed in group 2, and if h(A) = 3, the student is placed in group 3.

Write a program to perform the operations count the number of students in each group, the student

list in a group as per the order of insertion, and the student list who belongs to the same branch in

a group.

Note: Assume all the students are from CS, EC, EE, or CE branches.

Input format:

First line of the input contains an integer n [1, 10³], the total number of students who are

participating in the event.

Next n consecutive line contains: first name, roll number, and age; separated by single space.

The input contains a character c followed by an integer k [0, 3] to display the count and

student list of the group k.

The input contains an integer m [0, 3], representing the group number, followed by two

characters representing the branch name (both uppercase and lowercase are considered the

same branch).

The input contains a character e to represent the end of the input.

Output format:

The output (if any) of each command should be printed on a separate line.

For input lines starting with the character c followed by an integer k [0, 3], prints an

integer x followed by x number of strings separated by a space.

For input lines starting with an integer m [0, 3] followed by two characters, prints the

strings (first name) separated by a space, if any student exit in the group m. Otherwise,

print -1.

Sample Input:

4

Veena B220016EC 19

Abu B210051CS 21

Ishan B190016CE 22

Aleena B200036EE 21

c 0

1 CS

c 1

c 2

c 3

3 EC

2 ec

e

Sample Output:

0

2

Abu

2 Abu Ishan

1 Veena

1 Aleena

-1

Veena