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Please Halloween Practices A 1999 Gallup survey of a random sample of 1005 adult Americans found that 69% planned to give out Halloween treats from

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Halloween Practices A 1999 Gallup survey of a random sample of 1005 adult Americans found that 69% planned to give out Halloween treats from the door of their home. a. Is 0.69 a parameter or a statistic? - Parameter, because it's a percentage/decimal - Parameter, because it came from all adults handing out treats - Parameter, because they did a survey (3:) Statistic, because this came from a sample - -Statistic, because it's a percentageidecimal D View Feedback Question 2 1 I 1 point b. Does this finding necessarily prove that 69% of all adult Americans planned to give out treats? '1; Yes. the parameter always matches the statistic I2: Yes, 69% represents the parameter {5:} No. this survey was in 1999 and opinions might have changed since then {E} No. this is only the statistic, and we have no way of knowing the exact parameter Yes. that is what the survey determined c. If the population proportion planning to give out treats were really 0.7. would the sample result have fallen within two standard deviations of 0.7 in the sampling distribution? - Yes: the sampling standard deviation is 0.014 so two standard deviations from 0.7 would be (0.672, 0.728) so 0.69 is within 2 standard deviations of the mean - No; the sampling standard deviation is 0.0002 so two standard deviations from 0.7 would be (0.6998, 0.7002] so 0.69 is not within 2 standard deviations of the mean - No; the sampling standard deviation is 0.014 so two standard deviations from 0.7 would be (0.686, 0.714) so 0.69 is not within 2 standard deviations of the mean - No; the sampling standard deviation is 0.0002 so two standard deviations from 0.7 would be (0.6996, 0.7004] so 0.69 is not within 2 standard deviations of the mean - Yes: the sampling standard deviation is 0.014 so two standard deviations from 0.7 would be (0.686, 0.714) so 0.69 is within 2 standard deviations of the mean - No; the sampling standard deviation is 0.014 so two standard deviations from 0.7 would be (0.672, 0.728) so 0.69 is not within 2 standard deviations of the mean - Yes: the sampling standard deviation is 0.0002 so two standard deviations from 0.7 would be (0.6996, 0.7004) so 0.69 is within 2 standard deviations of the mean (3:) Yes: the sampling standard deviation is 0.0002 so two standard deviations from 0.7 would be [0.6993, 0.7002) so 0.69 is within 2 standard deviations of the mean c. If the population proportion planning to give out treats were really 0.64. would the sample result have fallen within two standard deviations of 0.64 in the sampling distribution? (El No; the sampling standard deviation is 0.0002 so two standard deviations from 0.64 would be (0.6398. 0.6402] so 0.69 is not within 2 standard deviations of the mean Yes: the sampling standard deviation is 0.0002 so two standard deviations from 0.64 would be (0.6396. 0.6404] so 0.69 is within 2 standard deviations of the mean No; the sampling standard deviation is 0.0002 so two standard deviations from 0.64 would be (0.6396, 0.6404) so 0.69 is not within 2 standard deviations of the mean Yes: the sampling standard deviation is 0.015 so two standard deviations from 0.64 would be [0.625, 0.655) so 0.69 is within 2 standard deviations of the mean No; the sampling standard deviation is 0.015 so two standard deviations from 0.64 would be (0.61, 0.67) so 0.69 is not within 2 standard deviations of the mean No; the sampling standard deviation is 0.015 so two standard deviations from 0.64 would be (0.625, 0.655) so 0.69 is not within 2 standard deviations of the mean Yes: the sampling standard deviation is 0.0002 so two standard deviations from 0.64 would be (0.6398, 0.6402] so 0.69 is within 2 standard deviations of the mean Yes: the sampling standard deviation is 0.015 so two standard deviations from 0.64 would be (0.61, 0.67) so 0.69 is within 2 standard deviations of the mean

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