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\f4 Find the general antiderivative of the function f(a:) = . Your answer will require fractional exponents. m = E - 2 Let f(a) = Enter the antiderivative of f(a). 1 - 2-2Write an ANTIDERIVATIVE F(x) of the function f(x) = 9 . sin (a + 4) Antiderivative of f(x): F(x) = Input x^2 for a , x^3 for a", sqrt(x+1) for va + 1 In(x+1) for the natural logarithm of x+1Match each integral with its result. - v /csc (x) dac a. - csc(x) + C b. tan(a) + C 1 - V dx x2 + 1 c. - cos(a) + C d. cot(ac) + C - v sin(x)dx e. cos (ac) + C - v /sec? (x) dac f. sin(a) + C g. tan (x) + C - v da V1 - x2 h. sin (a) + C i. - cot(ac) + C - v /csc(x) cot(x) dac j. sec(ac) + C - v /sec(x )tan(x)da k. cos(a) + C - v /cos( ze) dacFind the antiderivative of f(x) = 6et such that F(0) = 15. F(x) =Consider the function f(a:) = . Let F(a:) be the antiderivative of at) with F(1) = 0. mm = Consider the function f(x) = - 1 sin(x) + 32. Let F(x) be the antiderivative of f (a) such that F(0) = - 3. Then F(a) =A ball is shot from the ground straight up into the air with initial velocity of 48 ft} sec. Assuming that the air resistance can be ignored, how high does it go? Hint: The acceleration due to gravity is 32 ft per second squared